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IgorLugansk [536]
2 years ago
8

Please help I will really appreciate it it's about systems of equation

Mathematics
1 answer:
ioda2 years ago
3 0
The answer is the letter c and d
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Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 7 cubic feet
olchik [2.2K]
V = (pi)r² h
v = (pi)5² h
v = 25(pi) h
take derivative with respect to h
dv/dh = 25(pi)

(dv/dt)*(dt/dh) = dv/dh

dv/dt is given to be 5 cm³
solved for dv/dh = 25(pi)

5(dt/dh) = 25(pi)
dt/dh = 25(pi)/5
dt/dh = 5(pi)

then the recipricol of dt/dh; we want to find dh/dt = 1/(5(pi))
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Which variable has the most impact on growing your money? If you could increase one of the variables in the compound interest fo
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I would increase the number and multiply

Step-by-step explanation:

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2 years ago
Help!! I hate geometryyyy
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Answer:

AFB, BDC, and FBD

Step-by-step explanation:


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3 years ago
A square-shaped patio has an area of 256ft squared. What are the dimensions of the patio?
olga nikolaevna [1]

Answer:

all sides are 16 ft

Step-by-step explanation:

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8 0
3 years ago
A farmer has a 100 ft by 200 ft rectangular field that he wants to increase by 15.5% by cultivating a strip of uniform width aro
Advocard [28]

Answer:

(a) The strip should be 5ft wide

(b) The strip around the outside field is 10ft wide.

Step-by-step explanation:

Given:

Length of the rectangular field, L= 200 ft

width of the rectangular field, w = 100 ft

Area of the rectangular field, A = 200ft x 100ft = 20000 ft^2

let the width of the strip = x

The strip around the outside field = 2x

If the field is increased by 15.5%

New area of the field = 1.155 x 20000 = 23,100 ft^2

The increase in area of the field = 3,100 ft

3,100 = New area of field - old area of the field

3100 = (200 + 2x)(100 + 2x) - 20000

3100 = 20000 + 400x 200x + 4x^2 - 20000

3100 = 600x + 4x^2

Divide through by 4

775 = 150x + x^2

x^2 + 150x - 775 = 0

Factorize

(x + 155)(x-5) = 0

x = 5 ft

The strip should be 5ft wide.

The strip around the outside field = 2 x 5 ft = 10 ft

Thus, the strip around the outside field is 10ft wide.

3 0
3 years ago
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