Of the cliff?
Projectile motion
In the problem we are asked to find a height of certain cliff when a motorcycle stunt driver zoom out horizontally at the end the cliff at an initial velocity. So we will use one of the kinematics equation for projectile motion,
y
=
v
o
y
t
+
1
2
g
t
where
v
o
y
is just equal to zero since we can assume that the driver zooms out horizontally,
g
=
9.8
m
/
s
2
and
t
is time after
Answer:
x = 0.237
y = 0.0789
Explanation:
Vector with direction 18.4° and magnitude 0.250 has x and y components of:
x = 0.250 cos 18.4°
x = 0.237
y = 0.250 sin 18.4°
y = 0.0789
Answer:
b. a massive collapsed star
Explanation:
A black hole in the universe is nothing but a massive collapsed star. When the size of the star crosses a particular limit it cannot holds its mass and it collapses under it own self. This is called supernova. A black hole is actually a region in space where gravity is so strong that even light cannot escape through it. Gravity so strong because the matter has been pressed into a tiny space. hence option b is correct
Unbalanced because if it is pushing then stopping, that means that it is unbalanced.
Answer:
Yes the valency of oxygen is 2
