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marshall27 [118]
3 years ago
5

Power output of an engine is with work (w= 60,000J) during 60 s Calculate the power of this work?

Physics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

Power = 1000 j/s

Explanation:

Given:

Work done W = 60,000 J

Time taken T = 60 s

Find:

Power

Computation:

Power = W/T

Power = 60,000 / 60

Power = 1000 j/s

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Which of the following measurements has two significant digits?
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two 2.5 kg balls move away from each other one traveling 3 m/s to the right the other 4 m/s to the left what is the magnitude of
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Answer:

2.5 kg.m/s

Explanation:

Taking left side as positive while right side direction as negative then

Momentum, p= mv where m is the mass of the object and v is the velocity of travel

Momentum for ball moving towards right side=mv=2.5*-3=-7.5 kg.m/s

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5 0
3 years ago
A ray of red light in air is incident at an angle of 30. on a
Vlad [161]

Answer:

20 degrees.

Explanation:

From Snell’s law of refraction:

sinθ1•n1 = sinθ2•n2

where θ1 is the incidence angle, θ2 is the refraction angle, n1 is the refraction index of light in medium1, and n2 is the refraction index for virgin olive oil. The incidence angle of the red light is θ1 = 30 degrees.

The red light is in air as medium1, so n1 (air) = 1.00029

So, to find θ2, the refracted angle:

sinθ1•1.00029 = sinθ2•1.464

sin(30)•1.00029 / 1.464 = sinθ2

0.5•1.00029 / 1.464 = sinθ2

sinθ2 = 0.3416291

θ2 = arcsin(0.3416291)

θ2 = 19.976 degrees

To the nearest degree,

θ2 = 20 degrees.

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2 years ago
What is the momentum of an 18-kg object moving at 0.5 m/s?
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sorry Idk the answer ..???

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