If there is electrochemical cell where Q = 0.0010 and K = 0.10 then the truth about Ecell and E°cell is,
Ecell is positive and E°cell is negative.
E° = (RT/nF) InQ = (RT/nF) × In(K/Q) = Positive.
Since ( K/Q) = 100 then In(K/Q) = positive
Answer:
A) The two genes are unlinked and are assorting independently, leading to a 1:1:1:1 ratio of phenotypes in the offspring.
Explanation:
The χ2 value means nothing on its own--it is used to find the probability that, assuming the hypothesis is true, the observed data set could have resulted from random fluctuations. A low probability suggests the observed data is not consistent with the hypothesis, and thus the hypothesis should be rejected. The hypothesis that you are testing are two genes are unlinked and are assorting independently, leading to a 1:1:1:1 ratio of phenotypes in the offspring.
Answer:
Real dinosaurs can not be studied because they died out many years ago. so this is how we are learning about the past
Explanation:
Answer:
The correct option is number 3. A deficit of appositional bone growth would not be life threatening.
Explanation:
Appositional bone growth can be defined as the thickening of the bones due to increase in the number of bone tissues at the surface. In this kind of bone growth, the diameter of the bone increases rather than the length of the bone. This can lead to deformation of the bone but it is not life-threatening.
Rest of the options 1, 2 and 3 are serious disorders and can eventually lead to death.
ATP
Explanation:
ATP is produced in the cells and its conversion to energy is a single-step process.
