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3 years ago

Simplify the expression and find the missing terms.

Mathematics

1 answer:

zysi [14]3 years ago

5 0

What are the terms? I want to help, but I can't without the terms.

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NO SPACES AND NO DECIMALS

KonstantinChe [14]

Answer:

Happy paws

y = 20 + 4x

Woof watchers

y = 9 + 5x

x = 11 hours

Step-by-step explanation:

Let

Number of hours = x

Total cost = y

Total cost = fixed cost + variable cost

The equations are:

Happy paws

y = 20 + 4x

Woof watchers

y = 9 + 5x

solve the equation to find for how many hours the total cost of the services is equal.

Equate total cost of both services

20 + 4x = 9 + 5x

Collect like terms

20 - 9 = 5x - 4x

11 = x

x = 11 hours

Check:

Happy paws

y = 20 + 4x

= 20 + 4(11)

= 20 + 44

= 64

Woof watchers

y = 9 + 5x

= 9 + 5(11)

= 9 + 55

= 64

6 0

3 years ago

Free 100 points if u know what dis is

kvasek [131]

Answer:

This is a picture of You

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the domain of ^3√x^4+9?

navik [9.2K]

That would be c

x could be any real number.

3 0

3 years ago

Does anyone know how to do this problem? If so please help so I could get it? Not only the answer but like the formula on how yo

nasty-shy [4]

Kg=1000g
0.25kg x1000g= 250g

3 0

2 years ago

Can SOMEBODYYY please do the maths!!! PLeassssssssssssseeeeeeee

Anna11 [10]

Answer:

<h2>see below</h2>

Step-by-step explanation:

<h3>Question-6:</h3>

we are given a equation

$\sf \displaystyle \: \log_{4}( - x) + \log_{4}( 6 - x) = 2$

to solve so

recall logarithm multiplication law:

$\sf \displaystyle \: \log_{4}( - x \times (6 - x)) = 2$

simplify multiplication:

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = 2$

remember $\displaystyle \log_{4}(4^2)=2$

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = \log_{4}( {4}^{2} )$

cancel out $\log_4$ from both sides:

$\sf \displaystyle \: - 6 x + {x}^{2} = {4}^{2}$

simplify squares:

$\sf \displaystyle \: - 6 x + {x}^{2} = 16$

move left hand side expression to right hand side and change its sign:

since we are moving left hand side expression to right hand side there'll be only 0 left in the left hand side

$\sf \displaystyle \: - 6 x + {x}^{2} - 16 = 0$

rewrite it to standard form i.e ax²+bx+c=0

$\sf \displaystyle \: {x}^{2} - 6x - 16 = 0$

rewrite -6x as 2x-8x:

$\sf \displaystyle \: {x}^{2} + 2x - 8x - 16 = 0$

factor out x and 8:

$\sf \displaystyle \: x {(x}^{} + 2) - 8(x + 2) = 0$

group:

$\sf \displaystyle \: (x - 8){(x}^{} + 2) = 0$

$\displaystyle \: x = 8 \\ x = - 2$

$\therefore \: x = - 2$

<h3>Question-7:</h3>

move left hand side log to right hand side:

$\displaystyle \: \log(x ) + \log(x - 21) = 2$

use mutilation logarithm rule;

$\displaystyle \: \log( {x}^{2} - 21x) = 2$

$\log(10^2)=2$ so

$\displaystyle \: \log( {x}^{2} - 21x) = \log({10}^{2} )$

cancel out log from both sides:

$\displaystyle \: {x}^{2} - 21x = 100$

make it standard form:

$\displaystyle \: {x}^{2} - 21x - 100= 0$

factor:

$\displaystyle \: {(x} + 4)(x - 25)= 0$

$\displaystyle \: x = 25$

5 0

2 years ago