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3 years ago

Help please what is the answer?

Mathematics

1 answer:

Dmitrij [34]3 years ago

8 0

(pemdas), parenthesis then exponents.
7 * 2 = 14
14^ 7 = 105413504

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Please help me with the question below.

DaniilM [7]

Answer:

Alicia is correct

Step-by-step explanation:

The triangles are similar, then ratios of corresponding sides are equal, that is

left triangle to right triangle gives

$\frac{r}{k}$ = $\frac{s}{m}$

Thus Alicia is correct. Jason has the incorrect sides on the second ratio

7 0

2 years ago

Read 2 more answers

(x5 + y5) ÷ (x + y) please answer ASAP

Shkiper50 [21]

Answer:

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

Step-by-step explanation:

Given the expression

$\left(x^5+y^5\right)\div \left(x+y\right)$

$\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}$

$x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)$

$=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}$

Cancel the common factor: x+y

$=x^4-x^3y+x^2y^2-xy^3+y^4$

Thus,

$\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4$

3 0

2 years ago

Math question:

Vera_Pavlovna [14]

Answer: 102

Step-by-step explanation:

4 0

3 years ago

Alliya spent $6.70 on 12 pencils at the store. Her cost included $0.46 sales tax. How much did each pencil cost before the sales

Kaylis [27]

52 cents would be the answer.

Hope this helped. Would you like me to explain how I got it?

6 0

3 years ago

Read 2 more answers

Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn

Vinil7 [7]

Answer:

$t_3 = -53\\\\\\t_7 = -17\\t_n= -80 +9n$

Step-by-step explanation:

Arithmetic sequence:

$\sf \boxed{t_n=a+(n-1)d}$

Here a is the first term and d is the common difference.

$t_{14}= 6$ ⇒ $\sf a + 13 d = 46$ ------------(I)

$\sf t_{20} = 100$ ⇒ a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1) a + 19d = 100

(II) a + 13d = 46

6d = 54

d = 54 ÷ 6

$\sf \boxed{d = 9}$

Substitute d = 9 in equation(I) and find 'a',

a + 13*9= 46

a + 117 = 46

a = 46 - 117

a = -71

$\sf t_3 = -71 + 2*9$

= -71 + 18

= -53

$\sf t_7 = -71 + 6*9$

= -71 + 54

= -17

$\sf t_n= -71 + (n-1)*9$

= -71 + 9*n - 1 *9

= -71 + 9n - 9

= -71 - 9 + 9n

= - 80 + 9n

5 0

1 year ago