Pushes and pulls are all kinds of force.
Answer:
denser media the speed is greater
Explanation:
The speed of sound is given by the relation

where B is the volume modulus and ρ the density of the medium
When analyzing the previous expression, the amplitude of the sound depends on the energy carried by the wave.
Wave speed, is given by the relationship between two magnitudes, we analyze their values for different media. The volume modulus for gases has values of the order of 10⁵ Pa, for liquids of the order of 10⁹ Pa and for solids of 10¹⁰ to 10¹¹ Pa, while the density has values of the order of 10⁻¹ to 10⁰ kg / m³ for gases for liquids 10³ kg / m³ and for solids of the order of 10³ to 10⁴ kg / m³
let's find the order of magnitude of the speed of sound
Gases
v =√ 10⁵/10⁰ = 300 m / s
liquids
v =√ 10⁹/10³ = 1000 m / s
solid
v = √ 10¹¹/ 10⁴ = 3000 m / s
We can see that in denser media the speed is greater
Answer:
The rocket has to be launched 8 m from the hoop
Explanation:
Let's analyze this problem, the rocket is on a car that moves horizontally, so the rocket also has the same speed as the car; The initial horizontal rocket speed is (v₀ₓ = 3.0 m/s).
On the other hand, when starting the engines we have a vertical force, which creates an acceleration in the vertical axis, let's use Newton's second law to find this vertical acceleration
F -W = m a
a = (F-mg) / m
a = F/m -g
a = 7.0/0.500 - 9.8
a = 4.2 m/s²
We see that we have a positive acceleration and that is what we are going to use in the parabolic motion equations
Let's look for the time it takes for the rocket to reach the height (y = 15m) of the hoop, when the rocket fires its initial vertical velocity is zero (I'm going = 0)
y =
t + ½ a t²
y = 0 + ½ a t²
t = √ 2y/a
t = √( 2 15 / 4.2)
t = 2.67 s
This time is also the one that takes in the horizontal movement, let's calculate how far it travels
x = v₀ₓ t
x = 3 2.67
x = 8 m
The rocket has to be launched 8 m from the hoop
Answer:
The graph shows direct proportion because it is a straight line
through the origin.
Explanation:
Answer:
Force to stretch the wire is 250 N
Explanation:
As we know that modulus of elasticity will remain the same for the wire if the applied stretch to the wire is within elastic limit
So we will have

now we have

so we can write it as


