Dx = 20m
V1 = 10m/s
g = 9.8m/s^2
(delta-t) = 2sec
dy = 19.6m
Answer:
power is the rate at which energy is transferred or converted
the unit of power is Watts
Answer: 3. F1 = F2
Explanation:
According to <u>Newton's law of Gravitation</u>, the force
exerted <u>between two bodies</u> or objects of masses
and
and separated by a distance
is equal to the product of their masses divided by the square of the distance:
(1)
Where
is the gravitational constant
Now, in the especific case of the Earth and the satellite, where the Earth has a mass
and satellite a mass
, being both separated a distance
, the force exerted by the Earth on the satellite is:
(2)
And the force exerted by the satellite on the Earth is:
(3)
As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

Answer:
The sum of all forces for the two objects with force of friction F and tension T are:
(i) m₁a₁ = F
(ii) m₂a₂ = T - F
1) no sliding infers: a₁ = a₂= a
The two equations become:
m₂a = T - m₁a
Solving for a:
a = T / (m₁+m₂) = 2.1 m/s²
2) Using equation(i):
F = m₁a = 51.1 N
3) The maximum friction is given by:
F = μsm₁g
Using equation(i) to find a₁ = a₂ = a:
a₁ = μs*g
Using equation(ii)
T = m₁μsg + m₂μsg = (m₁ + m₂)μsg = 851.6 N
4) The kinetic friction is given by: F = μkm₁g
Using equation (i) and the kinetic friction:
a₁ = μkg = 6.1 m/s²
5) Using equation(ii) and the kinetic friction:
m₂a₂ = T - μkm₁g
a₂ = (T - μkm₁g)/m₂ = 12.1 m/s²
Explanation:
It is given that,
When a high-energy proton or pion traveling near the speed of light collides with a nucleus, 
Speed of light, 
Let t is the time interval required for the strong interaction to occur. The speed is given by :




So, the time interval required for the strong interaction to occur is
. Hence, this is the required solution.