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lana66690 [7]
3 years ago
15

The midpoint between y and 33is -7. Find Y

Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

-43

Step-by-step explanation:

-7 is exactly 36 units away from 33 so we need to go 36 in the other direction to find the value of y

since it's distance I'm not using negatives rn

36+7= 43

a pic if u don't believe me

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Frank bought 2 CDs that were each the same price. Including sales tax, he paid a total of 24.20 Each CD had a tax of 0.60 What w
stira [4]

Answer:

11.5

Step-by-step explanation:

Frank paid a total of 24.2 for the 2 CDs, so, for each CD, he paid the total value divided by two:

Price of each CD = 24.2 / 2 = 12.1

Each CD had a tax of 0.6, so, to calculate the price of each CD before tax, we just subtract the price of each CD by the value of the tax for each CD:

Price of each CD before tax = 12.1 - 0.6 = 11.5

The price of each CD before tax is 11.5

8 0
3 years ago
Find the area of the region under the graph of f on [a, b].<br> f(x) = x2 − 8x + 17; [−1, 2]
Harman [31]

Answer:

The area is 42 area units.

Step-by-step explanation:

The area of a function f(x) on an interval [a,b] is given by:

A = \int\limits^a_b {f(x)} \, dx

Applying to this question:

A = \int\limits^-1_2 {x^2 - 8x + 17} \, dx

Then

F(x) = \frac{x^{3}}{3} - 4x^{2} + 17x

A = F(2) - F(-1)

F(2) = frac{2^{3}}{3} - 4*2^{2} + 17*2 = \frac{8}{3} + 18 = \frac{8 + 3*18}{3} = \frac{62}[3}

F(-1) = frac{(-1)^{3}}{3} - 4*(-1)^{2} + 17*(-1) = -\frac{1}{3} - 21 = \frac{-1 - 21*3}{3} = -\frac{64}[3}

A = F(2) - F(-1) = \frac{62}[3} - (-\frac{64}[3}) = \frac{62+64}{3} = 42

The area is 42 area units.

5 0
3 years ago
Solve for x.<br> x2 + 8x + 15 = 0
likoan [24]

Answer: x=−3 or x=−5

Step-by-step explanation:

Step 1: Factor left side of equation.

(x+3)(x+5)=0

Step 2: Set factors equal to 0.

x+3=0 or x+5=0

x=−3 or x=−5

7 0
3 years ago
Can anyone help me with this.
Minchanka [31]

Answer:

a) third; from left most graph

b) fourth; right most graph

Step-by-step explanation:

Part a)

The graph is between the speed and time.

Nicole begin jogging faster and faster i.e. speed is increasing w.r.t time thus we have linear line in beginning.

Then she hits a comfortable speed and stayed at it i.e. speed remained constant for that time. Thus we have a straight line.

After that she gradually slows down,i.e speed is decreasing w.r.t time. Thus we have decreasing linear line.

So the graph shape is linear line with increasing slope-a constant straight line-linear line with decreasing slope

which is the third; from left most graph in option

Part b)

The graph is between Distance to campus and time.

As Dale is hiking towards campus, distance should decrease w.r.t time.

In beginning, he is hiking at constant speed towards campus thus the distance towards the campus is decreasing w.r.t time. We get a decreasing linear line.

*Note: here constant speed is not important, instead hiking towards i.e. the direction is important because of the campus distance covered

Then he sees a snake and turn and runs the other way. Thus now the distance towards the campus is increasing. And we get increasing linear line.

*Note running other way is important because of the campus distance covered

After that, he sits for a while i.e he stops and so the distance towards campus also become constant w.r.t time. we get a straight line on the graph.

So the graph shape is linear line with decreasing slope-linear line with increasing slope-a constant straight line

which is the right-most graph in option !

4 0
3 years ago
A mistake was made in the steps shown to simplify the expression. Which step includes the mistake?
Zolol [24]

Answer:

step 4

Step-by-step explanation:

8 0
3 years ago
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