Isolate the v.
a = v^2/2
First multiply 2 to both sides
a(2) = v^2/2(2)
2a = v^2
Isolate the v, root both sides
√2a = √v^2
✓2a = v
✓2a = v should be your answer
Hope this helps
Well! See ,If the endpoints are (x1,y1) & (x2,y2) then mid-point is given by (x1+x2)/2,
(y1+y2)/2
Here in this question endpoints given for the line segment are (-4,2) , (2,4) so we have to find mid-point for x and y co-ordinates by applying above rule.
So, the mid-point we get is (-4+2)/2 , (2+4)/2.
i.e. (-1,3) which lies in 2nd Co-ordinate!
Hope it helps!!
Answer:
25
Step-by-step explanation:
25x14=350
(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) =
(2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
