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BigorU [14]
3 years ago
5

Find the 11th term in the following geometric sequence. -5,-10,-20,-40

Mathematics
1 answer:
kondaur [170]3 years ago
5 0
-80....each number is double the one before it
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Is this function linear or nonlinear?
Sergio039 [100]

The answer is nonlinear. It goes in a sharp downward curve, whereas a linear function is a straight line.

7 0
3 years ago
Nick and Liz have decided to move from the city to the suburbs. This means that they will have to make the essential purchase of
sineoko [7]

Answer:

$=19400

Step-by-step explanation:

Average prices= $18,500

Number of prices that were quoted= 7

Expected sum that produces this mean= 7*18,500=$129,500

Sum of quoted prices=

$(15,500+ 18,800+ 16,900+ 19,900+18,000+21,000) =$110100

Next price to be quoted will be ;

$129,500-$110,100

$=19400

6 0
3 years ago
Peter saved up $20,000 in an account earning a nominal 5% per year compounded continuously. How much was in the account at the e
kykrilka [37]

Answer:

$22,050

Step-by-step explanation:

$20,000+5%=$21,000

$21,000+5%=$22,050

3 0
3 years ago
If we ignore wind resistance the time in seconds it takes for an object to fall S feet by t=1/4[s. Thus an object will fall 100
Nataly [62]

Answer:

The time taken by object to dropped the distance of 1089 feet .

Step-by-step explanation:

Given as :

The distance cover by object to fall = 100 feet

The Time taken by the object to fall = 2.5 seconds

Let the speed of the object = s feet/ sec

Now, Speed = \dfrac{\textrm Distance}{\textrm Time}

or, Speed = \dfrac{\textrm 100}{\textrm 2.5}

∴ Speed = 40 feet per sec

Now, again

Distance cover by object = 1089 feet

∵ Speed of object = 40 feet per sec

Let The Time taken at 40 feet per sec = t sec

So, Time = \dfrac{\textrm Distance}{\textrm Speed}

Or , Time = \dfrac{\textrm 1089}{\textrm 40}

or, t = 27.22 seconds

Hence The time taken by object to dropped the distance of 1089 feet . Answer

4 0
4 years ago
Can someone help? Please explain as well?
irga5000 [103]
Multiply 29 cm and 18 cm
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3 years ago
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