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Varvara68 [4.7K]

2 years ago

15

Four students did a 400 meter sprint relay. Henry's time was 51.10 seconds, Cathryn's time was 45.26 seconds, Grayson's time was

101.92 seconds, and Woody's time was 62.14 seconds. What was their total time?

1 answer:

mylen [45]2 years ago

8 0

Answer:

260.42 you add them because it want the total time of all of them

Step-by-step explanation:

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5 bruhsjddjdjdkrmdivi kfkvkdk rkvkriv

4 0

3 years ago

Solve the expression by using the model below. Each strip represents one whole.

Genrish500 [490]

Answer:

Please include a photo of model please!

Step-by-step explanation:

8 0

2 years ago

Write and simplify an expression that represents the perimeter of the parallelogram. 8x + 1 and 6x - 4Perimeter:

Gelneren [198K]

Answer:

2(8x+1)+2(6x-4)

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Step-by-step explanation:

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3 0

2 years ago

A single die is rolled. Find the probability of rolling an oddnumber or a number less than 6.

mina [271]

Given

A single die is rolled.

To find the probability of rolling an odd number or a number less than 6.

Explanation:

It is given that,

A single die is rolled.

Then, the sample space is,

$\begin{gathered} S=\lbrace1,2,3,4,5,6\rbrace \\ n(S)=6 \end{gathered}$

Let A be the event of getting an odd number.

Then,

$\begin{gathered} A=\lbrace1,3,5\rbrace \\ n(A)=3 \end{gathered}$

Let B be the event of getting a number less than 6.

Then,

$\begin{gathered} B=\lbrace1,2,3,4,5\rbrace \\ n(B)=5 \end{gathered}$

Also,

$\begin{gathered} A\cap B=\lbrace1,3,5\rbrace \\ n(A\cap B)=3 \end{gathered}$

Therefore,

$\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ =\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{n(A\cap B)}{n(S)} \\ =\frac{3}{6}+\frac{5}{6}-\frac{3}{6} \\ =\frac{3+5-3}{6} \\ =\frac{5}{6} \end{gathered}$

Hence, the answer is 5/6.

5 0

7 months ago

Read 2 more answers

In the diagram, segments BG,CF, and DE are parallel. The length of segment BD is 6.32 feet, and the length of segment De is 6 fe

Lena [83]

Similar triangles are triangles with equal corresponding angles and proportionate sides. Thus the pair of similar triangles will be:
Δ ADE≈ΔACF≈Δ ABG
this implies that the corresponding angles are equal. Thus:
∠B=∠C=∠D
∠G=∠F=∠E
and the ratio of corresponding sides are equal

6 0

2 years ago