Question

The choices are =,>,< and greater than or equal to

Answer 1

Answer:

We conclude that

$4\frac{2}{3}$    >   $\sqrt{21}$

Step-by-step explanation:

Given

• $\sqrt{21}$

• $4\frac{2}{3}$

as

$\:\sqrt{21}=4.58$

and

$4\frac{2}{3}$

Convert mixed numbers to improper fraction:

$a\frac{b}{c}=\frac{a\cdot \:c+b}{c}$

so

$4\frac{2}{3}=\frac{4\cdot 3+2}{3}=\frac{14}{3}=4.67$

Thus,

$\:\sqrt{21}=4.58$

$4\frac{2}{3}=4.67$

as

4.67      >       4.58

so

$4\frac{2}{3}$         >        $\sqrt{21}$

Hence, we conclude that

$4\frac{2}{3}$    >   $\sqrt{21}$