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yulyashka [42]
3 years ago
14

What is the equation of the line that passes through the points (-2,3) and (1,9)?

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

Solution given:

(x1,y1)=(-2,3)

(x2,y2)=(1,9)

we have

equation of line

(y-y1)=\frac{y2-y1}{x2-x1}(x-x1)

(y-3)=\frac{9-3}{1+2}(x+2)

y-3=2x+4

2x-y+4+3=0

2x-y+7=0;is a required equation.

stellarik [79]3 years ago
5 0
The answer is y= -3x - 3

hope that helps!

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Write an inequality that represents eight less than 3 times a number is more than 22​
SCORPION-xisa [38]

Answer:

3x-8>22

Step-by-step explanation:

3 times a number = 3x

8 less = -8

more than 22 = >22

Put them together and you get:

3x-8>22

8 0
3 years ago
Find the center and radius of the attached circle that goes through the point (-4,-1)
murzikaleks [220]

Answer:

I think the Radius is 3. I'm not really sure, don't quote me on it. K?

Step-by-step explanation:

3 0
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7. The dimensions of a lawn shaped like a trapezoid are given in meters.
Veronika [31]

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)
Deffense [45]

Answer:

Part 1) MD=9\ units

Part 2) DC=12\ units

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

so

In this problem

MD=ME=MF ------> is the radius of a circle inscribed inside the triangle

we have that

MF=9\ units

therefore

ME=9\ units

MD=9\ units

Step 2

Find the length of DC

we know that

In the right triangle MDC

Applying the Pythagoras theorem

MC^{2} =MD^{2}+DC^{2}

we have

MD=9\ units

MC=15\ units

substitute

15^{2} =9^{2}+DC^{2}

DC^{2}=225-81

DC=\sqrt{144}\ units

DC=12\ units

6 0
3 years ago
Complete the ordered pair for the given equation. (_,-1);y=-3/5x-7
Fiesta28 [93]
Hi!

So for this problem, we're given the y-coordinate and we can plug that in for y in the equation. So let's do that

-1 = -3/5x - 7
6 = -3/5x
30 = -3x
-10 = x

The missing coordinate would be x, assuming that the equation was y = (-3/5)x - 7

3 0
3 years ago
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