What is the equation of the line that passes through the points (-2,3) and (1,9)?
2 answers:
Answer:
Solution given:
(x1,y1)=(-2,3)
(x2,y2)=(1,9)
we have
equation of line
(y-y1)=
(x-x1)
(y-3)=
(x+2)
y-3=2x+4
2x-y+4+3=0
2x-y+7=0;is a required equation.
The answer is y= -3x - 3
hope that helps!
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