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SpyIntel [72]
3 years ago
9

during a basketball game justin attempted 40 shots and made 18. He says he made 35% of the shots is justin correct

Mathematics
1 answer:
Vikentia [17]3 years ago
5 0

Answer:

No, Justin is incorrect.

Step-by-step explanation:

1. To find how much 18/40 as a percent is, we just multiply 18/40 by 100:

  • \frac{18}{40} * 100
  • \frac{9}{20} * 100
  • \frac{900}{20}
  • 45

2. As you can see, 18/40 as a percent is 45%, not 35%. Therefore, Justin is incorrect.

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A wrestling match has eliminations each round. The table below shows the number of wrestlers in each of the first 4 rounds of th
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round(x)&\boxed{1}&2&3&\boxed{4}\\\\
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slope = {{ m}}= \cfrac{rise}{run} \implies 
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f(x)=   \qquad 
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Read 2 more answers
MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
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