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enot [183]
3 years ago
12

Help plz and please make sure it’s right :)

Mathematics
1 answer:
romanna [79]3 years ago
8 0
(180-76) + 42 + (180-x) = 180
104 + 42 + 180 - x = 180
-x = 180 - 326
x = 146°
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Is anyone able to help me with this?
Semenov [28]
I am able to help you but not give you the answer.

Step By Step Explanation- Find the Area to the Triangle, After you find the answer to that, Find the area to the square then subtract the Square by the triangle and you get your answer!
8 0
3 years ago
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Is the relationship shown by the data linear? How can you tell if it is or is not? If so, model the data with an equation.
yuradex [85]

Hello from MrBillDoesMath!

Answer:    The relationship is linear. The equation is y = 2x + 19

Discussion:

When x changes from -7 to -5 ( and increment of of +2),  y changes from 5 to 9 ( an increment of +4). When x changes from 5 to -3 (an increment of +2) , y changes from 9 to 13 (an increment of +4)... and so on.....

So far, when x changes by 2, y changes by 4.  This means the data falls on a line (so is linear). In fact,

(change in y) /  (change in x) = 4/2 = 2 =  slope of line.

so  y = 2x + b. As the line passes through the point ( -7, 5)

5 = 2 (-7) + b    or

5 = -14 + b       or ( adding 14 to both sides)

5 + 14 = 19  = b.

Hence the equitation the line is  y = 2x + 19

Thank you,

MrB

6 0
3 years ago
An elevator has a placard stating that the maximum capacity is 1296 lb long dash — 8 passengers.​ So, 8 adult male passengers ca
Masja [62]

Answer:

There is a 98.26% probability that it is overloaded.

This elevator does not appear to be safe.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of males are normally distributed with a mean of 170 lb, so \mu = 170

They have a standard deviation of standard deviation of 29 lb, so \sigma = 29.

We have a sample of 8 adults, so we have to find the standard deviation of the sample to use in the place of \sigma in the Z score formula.

s = \frac{\sigma}{8} = \frac{29}{8} = 3.625

Find the probability that it is overloaded because they have a mean weight greater than 162 lb, so X = 162

Z = \frac{X - \mu}{\sigma}

Z = \frac{162 - 170}{3.625}

Z = -2.21

Z = -2.21 has a pvalue 0.0174.

So, there is a 1-0.0174 = 0.9826 = 98.26% probability that it is overloaded.

Any probability that is above 95% is considerer unusually high. So, this elevator does not appear to be safe, since there is a 98.26% probability that it is overloaded.

8 0
3 years ago
The number of customers in a grocery store is modeled by the function y -X? + 10x + 50, where y is
vova2212 [387]

Using the vertex of the quadratic function, it is found that:

a) The maximum number of customers in the store is at 12 P.M.

b) 75 customers are in the store at this time.

The number of customers in x hours after 7 AM is given by:

y = -x^2 + 10x + 50

Which is a quadratic equation with coefficients a = -1, b = 10, c = 50

Item a:

The maximum value, considering that a < 0, happens at:

x_v = -\frac{b}{2a}

Hence:

x_v = -\frac{10}{2(-1)} = 5

5 hours after 7 A.M, hence, the maximum number of customers in the store is at 12 P.M.

Item b:

The value is y(5), hence:

y(5) = -(5)^2 + 10(5) + 50 = 75

75 customers are in the store at this time.

A similar problem is given at brainly.com/question/24713268

7 0
2 years ago
I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}&#10;y=&2(&1x&-2)^2&-4\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\&#10;\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\&#10;D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
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