The answer is D. trust me, i’m super good at math.
Make a substitution:

Then the system becomes
![\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%5Cdfrac%7B2%5Csqrt%5B3%5D%7Bu%7D%7D%7Bu-v%7D%2B%5Cdfrac%7B2%5Csqrt%5B3%5D%7Bu%7D%7D%7Bu%2Bv%7D%3D%5Cdfrac%7B81%7D%7B182%7D%5C%5C%5C%5C%5Cdfrac%7B2%5Csqrt%5B3%5D%7Bv%7D%7D%7Bu-v%7D-%5Cdfrac%7B2%5Csqrt%5B3%5D%7Bv%7D%7D%7Bu%2Bv%7D%3D%5Cdfrac1%7B182%7D%5Cend%7Bcases%7D)
Simplifying the equations gives
![\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%5Cdfrac%7B4%5Csqrt%5B3%5D%7Bu%5E4%7D%7D%7Bu%5E2-v%5E2%7D%3D%5Cdfrac%7B81%7D%7B182%7D%5C%5C%5C%5C%5Cdfrac%7B4%5Csqrt%5B3%5D%7Bv%5E4%7D%7D%7Bu%5E2-v%5E2%7D%3D%5Cdfrac1%7B182%7D%5Cend%7Bcases%7D)
which is to say,
![\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%5Csqrt%5B3%5D%7Bu%5E4%7D%7D%7Bu%5E2-v%5E2%7D%3D%5Cdfrac%7B81%5Ctimes4%5Csqrt%5B3%5D%7Bv%5E4%7D%7D%7Bu%5E2-v%5E2%7D)
![\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81](https://tex.z-dn.net/?f=%5Cimplies%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%20uv%5Cright%29%5E4%7D%3D81)


Substituting this into the new system gives
![\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1](https://tex.z-dn.net/?f=%5Cdfrac%7B4%5Csqrt%5B3%5D%7Bv%5E4%7D%7D%7B%28%5Cpm27v%29%5E2-v%5E2%7D%3D%5Cdfrac1%7B182%7D%5Cimplies%5Cdfrac1%7Bv%5E2%7D%3D1%5Cimplies%20v%3D%5Cpm1)

Then

(meaning two solutions are (7, 13) and (-7, -13))
Using linear combination method to solve the system of equations 3x - 8y = 7 and x + 2y = -7 is (x, y) = (-3, -2)
<h3><u>
Solution:</u></h3>
Given that, a system of equations are:
3x – 8y = 7 ⇒ (1) and x + 2y = - 7 ⇒ (2)
We have to solve the system of equations using linear combination method and find their solution.
Linear combination is the process of adding two algebraic equations so that one of the variables is eliminated. Addition or subtraction can be used to perform a linear combination.
Now, let us multiply equation (2) with 4 so that y coefficients will be equal numerically.
4x + 8y = -28 ⇒ (3)
Now, add (1) and (3)
3x – 8y = 7
4x + 8y = - 28
----------------
7x + 0 = - 21
7x = -21
x = - 3
Now, substitute "x" value in (2)
(2) ⇒ -3 + 2y = - 7
2y = 3 – 7
2y = - 4
y = -2
Hence, the solution for the given two system of equations is (-3, -2)
Answer:
108 dollars
Step-by-step explanation:
First, let's convert 6% to a decimal.
We get 0.06 because we multiplied (or divided by 100) it by 1/100.
Now, let's do 0.06 * 300 to get interest on one year. This equals to 18$
Let's now do 18 * 6 to get
108 dollars
Answer:
The angle must be at 3.81°
Step-by-step explanation:
The horizontal distance of the shooting range is 60 yards
The height of the target is 12ft.
We'll have to convert the value of the height from ft to yards.
1 yards = 3 foot
X yards = 12ft
X = 4yards.
The height of the target is 4 yards.
Now, to find the angle at which the shooter makes with the zenith of the target(height), we'll have to use use SOHCAHTOA
To know which of the rules we'll follow, a pictorial illustration of the values will help
(See attached document for better illustration).
From the diagram, we can see we have values at both opposite and adjacent.
Opposite = 4
Adjacent = 60
Hence we can use Tanθ = opposite/ adjacent
Tanθ = 4 / 60
Tanθ = 0.067
θ = Tan⁻0.067
θ = 3.81°
The angle at which the rifle must be set to hit the target is 3.81°