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docker41 [41]
2 years ago
6

At the beginning of March, a store bought a rake at a cost of 9$ and marked it up 130%. At the end of the month, the rake had no

t sold, so the store marked it down 50%. What is the discounted price?
Mathematics
1 answer:
docker41 [41]2 years ago
8 0

Answer:

the new discounted price is $5.85

Step-by-step explanation:

First convert 130% into a decimal: 130 ÷ 100 = 1.3

Next multiply 1.3 by 9: 9 x 1.3 = 11.7

Then convert 50% into a decimal: 50 ÷ 100 = 0.5

Last multiply 11.7 by 0.5: 11.7 x 0.5 = 5.85

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Using the t-distribution, it is found that:

a. The <u>margin of error</u> is of 4.7 homes.

b. The 98% confidence interval for the population mean is (19.3, 28.7).

The information given in the text is:

  • Sample mean of \overline{x} = 24.
  • Sample standard deviation of s = 9.
  • Sample size of n = 23.

We are given the <u>standard deviation for the sample</u>, which is why the t-distribution is used to solve this question.

The confidence interval is:

\overline{x} \pm M

The margin of error is:

M = t\frac{s}{\sqrt{n}}

Item a:

The critical value, using a t-distribution calculator, for a two-tailed <u>98% confidence interval</u>, with 23 - 1 = <u>22 df</u>, is t = 2.508.

Then, the <em>margin of error</em> is:

M = t\frac{s}{\sqrt{n}} = 2.508\frac{9}{\sqrt{23}} = 4.7

Item b:

The interval is:

\overline{x} - M = 24 - 4.7 = 19.3

\overline{x} + M = 24 + 4.7 = 28.7

The 98% confidence interval for the population mean is (19.3, 28.7).

A similar problem is given at brainly.com/question/15180581

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