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3 years ago

Help me please someone

Biology

1 answer:

Vaselesa [24]3 years ago

3 0

Answer:

classification pyramid

Explanation:

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dexar [7]

Answer:

even me I don't kno haha lol

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3 years ago

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What are the 2 ways plants use energy?

Alex777 [14]

Answer:

What are the 2 ways plants use energy?

Explanation:

This process uses solar energy to convert carbon dioxide and water into energy in the form of carbohydrates. It is a two-part process. First, the energy from solar radiation is trapped in the plant. Secondly, that energy is used to break down carbon dioxide and form glucose, the main energy molecule in plants.

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3 years ago

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Gregor Mendel called the generation created by crossbreeding the parental generation the

Paraphin [41]

Answer:

First filial generation.

Explanation:

Mendel is known as the father of genetics. He formulated the law of segregation and law of independent assortment by working on the pea plant.

The Mendel first crossed the pure breed line parents and obtained the first filial generation. The F1 generation is obtained by the cross breeding of the parental generation.

Thus, the correct answer is option (D).

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3 years ago

si se sustituye una pirimidina por una purina en una sola posicion de una hebra de una doble helice de adn ¿que ocurriría?

denpristay [2]

Answer:

gfddgfg

Explanation:

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3 years ago

scalloped (sd) is an X-linked recessive and ebony (e) is an autosomal recessive mutation. What proportion of scalloped, ebony fe

alisha [4.7K]

Answer:

1/16

Explanation:

scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
ebony (e) is an autosomal mutation recessive to e+ (wild type).

The two genes are independent because they are located on different chromosomes.

<h3>Parental generation:</h3>

True breeding scalloped female wild type for ebony (Xsd Xsd e+e+) mates with a true breeding male mutant only for ebony (Xsd+ Y ee).

The female only produces Xsd e+ gametes. The male produces Xsd+ e or Y e gametes. Therefore, the F1 females will have the genotype Xsd Xsd+ e e+ and the F1 males will have the genotype Xsd Y e e+.

If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a Xsd Xsd e e genotype and appear in a 1/16 proportion.

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3 years ago