A solution contains 50g of kcl per 100g of water at 100 degrees Celsius. Is solution saturated, unsaturated or supersaturated
1 answer:
<u>Answer:</u>
The solution is Unsaturated
<u>Explanation:</u>
Nature of solution (saturated , unsaturated or supersaturated) depends on solubility of that salt in water. Because solubility of KCl in water is about 360.5g / 100g of water at 100 degree celcius. So, some amount of KCl will remain undissolved in water.Hence, it is an unsaturated solution.
We are given 50g of KCl per 100g water at 100 degrees celcius,
now mass of KCl = mass of K + mass of Cl = 39+35.5 = 74.5g
So, Molar mass of KCl = = 0.6711 moles
And Molar mass of 100g water = = 5.55moles
Now, to find property of solution we divide the molar masses,
= 12.07% this is the quantity of solute in water which makes the solution an unsaturated solution.
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The first step, would be to understand that when the transition is well-defined as the one on the attached file, we can just identify the temperature by just reading the value on the graph, at the time the slope has a pronounced change. For instance, on the attached, the transition occurs after about 43 seconds and the freezing point will be about 4 °C.
However, when we cannot identify a pronounced change in the slope, it will be necessary to use a linear fit method (such as minimum squares) to figure out the equation for each segmented line having a significantly different slope and then equal them so that we can numerically solve for the intercept.
As an example, imagine two of the segmented lines have the following equations after applying the linear fit method:
First of all, we equal them to find the x-value, in this case the time at which the freezing point takes place:
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