Answer:
Answer is 264 cm^2
Step-by-step explanation:
Answer:
660 square feet
Step-by-step explanation:
1 chain = 66 feet
Length ( l ) = 66 feet
Breadth ( b ) = 10 feet
To find :
The area of a cricket pitch in square feet = ?
The area of a cricket pitch in square feet will be in the shape of rectangle.
Formula : -
Area of a rectangle = lb
Area of a rectangle
= 66 x 10
= 660 square feet
Therefore,
660 square feet is the area of a cricket pitch.
Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Answer:
2nd statement describes the relation between graph of f(x) and graph of g(x).
Step-by-step explanation:
We are told that graph of
and we are asked to choose the correct statement that describes the relation between graph of f(x) and graph of g(x).
The rules for the translation are as follows:



Upon comparing our given translation with above rules we can see that our parent graph f(x) is shifted down by 1 unit to get our new graph g(x).
Therefore, graph of g(x) is the graph of f(x) translated 1 unit down and 2nd option is the right choice.
Answer:
The area of LQM is 
Step-by-step explanation:
Given
Area of PNQ = 8
Area of LPQ = 16
See attachment for triangles
The area of PNQ is calculated as:

Substitute 8 for Area


The area of LPQ is calculated as:

Substitute 16 for Area

From the attachment:

Make LP the subject

So:

We have:
and 
Equate both expressions:

Divide both sides by PQ

Multiply both sides by 2


Since PNQ is similar to LNM, the following equivalent ratios exist:

Substitute 



Area of LQM is:

This gives:


Recall that:

So:

