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jok3333 [9.3K]
3 years ago
12

Cecilia has $900 in an account earning 3.8% simple interest. how much more interest would her account earn in 5 years with annua

lly-compounded interest?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0
Simple interest
I=900*0.038*5==171
Compound interest
A=900×(1.038)^(5)
A=1,084.5
I=A-p=1084.5-900=184.5
So simple interest-compound interest
184.5-171==13.5 the answer
Hope it helps :-)
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Soloha48 [4]

Answer:

Jane: 37 years old

Anne: 17

Step-by-step explanation:

Jane 12 years ago: 5x

Anne 12 years ago: x

In three years into the future:

Jane: 5x+15

Anne: x+15

CURRENT TIME:

Jane: 5x+12

Anne: x+12

Equation (using 3 years into the future ages): 5x+15=2(x+15)

5x+15=2x+30

(subtract 15 from both sides)

5x=2x+15

3x=15

x=5

Therefore, Jane is 37 years old and Anne is 17 years old.

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3 years ago
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Nikolay [14]

Answer:  c. z = 1.35; Reject the null hypothesis

Step-by-step explanation:

Let \mu be the average life expectancy of its batteries.

As per given , we have

Null hypothesis : H_0 : \mu =135

Alternative hypothesis : H_a : \mu >135

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Test statistic : \dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overlien{x}= sample mean

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For n=42,\ \overline{x}=140\ \&\ \sigma=24, we have

z=\dfrac{140-135}{\dfrac{24}{\sqrt{42}}}=1.35015431217\approx1.35

Critical one-tailed test value for 0.10 significance level :

z_{0.1}=1.28

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[When critical value is less than the test statistic value , we reject the null hypothesis .]

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Vera_Pavlovna [14]
Little late, but your answer would be 133 pieces of candy corn. 

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2 years ago
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OlgaM077 [116]

Answer:

Answer:

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Step-by-step explanation:

You kind of just plug in the numbers.

a vertical stretch by a factor of ​5: y = 5x^3

a reflection across the​ x-axis: y = -5x^3

a vertical translation 1 unit down: -5x^3 - 1

a horizontal translation 7 units right: -5(x - 7)^3 -1

Step-by-step explanation:

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