Determine whether 2, 5, 9, 14, . . . is an arithmetic sequence

Mathematics

2 answers:

guapka [62]3 years ago

8 0

Answer:

no because they do not go up by the same number plz mark brainiest

Step-by-step explanation:

labwork [276]3 years ago

7 0

No it’s not because it’s not in a specific order

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..vertex: (4, -1)<br> f(3) = -6

s344n2d4d5 [400]

Answer:

$\huge\boxed{f(x)=-5(x-4)^2-1=-5x^2+40x-81}$

Step-by-step explanation:

The vertex form of an equation of a parabola:

$f(x)=a(x-h)^2+k$

$(h;\ k)$ - vertex

We have

vertex $(4;\ -1)\to h=4;\ k=-1$

$f(3)=-6$

Therefore we have:

$f(x)=a(x-4)^2+(-1)=a(x-4)^2-1$

Substitute $x=3$ and $f(3)=-6$

$a(3-4)^2-1=-6\qquad|\text{add 1 to both sides}\\\\a(-1)^2=-6+1\\\\a(1)=-5\\\\a=-5$

Finally:

$f(x)=-5(x-4)^2-1=-5(x^2-2(x)(4)+4^2)-1\\\\=-5(x^2-8x+16)-1=-5x^2+(-5)(-8x)+(-5)(16)-1\\\\=-5x^2+40x-80-1=-5x^2+40x-81$

4 0

3 years ago

Graph the function. For the function whose graph is shown below, which is the correct formula for the function? y = –x – 1 y = x

rusak2 [61]

You forgot to mention the graph.
So, I make the graph of both given functions and you will compare your graph with them.

First, y= -x-1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,-1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.

Second, y= x+1
put y=0 you get point (-1,0) called x-intercept
put x=0 you get point (0,1) called y-intercept
join both the points, you will get the graph
Graph is attached in the picture.