Determine whether 2, 5, 9, 14, . . . is an arithmetic sequence

Mathematics

2 answers:

guapka [62]3 years ago

8 0

Answer:

no because they do not go up by the same number plz mark brainiest

Step-by-step explanation:

labwork [276]3 years ago

7 0

No it’s not because it’s not in a specific order

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4 years ago

Read 2 more answers

What multiplies to -29 and adds to 1

Margarita [4]

First set up equation
x times y=xy

so
xy=-29
and
x+y=1
subtract x from both sides
y=1-x
subsitute 1-x for y in first equation
x(1-x)=-29
distribute
x-x^2=-29
add x^2 to both sides
x=-29+x^2
subtract x from both sides
0=x^2-x-29
so we can use the quadratic formula to solve for x if the equation=0 and it is in ax^2+bx+c form so

if
ax+bx+c=0 then x= $\frac{ -b+/-\sqrt{b^2-4ac} }{2a}$ that means x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$ or x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$ so

x^2-x-29
a=1
b=-1
c=-29
$\frac{ -(-1)-\sqrt{-1^2-4(1)(-29)} }{2(1)}$ = $\frac{ +1-\sqrt{1^2-(-116)} }{2(1)}=\frac{ +1-\sqrt{1^2+116} }{2}=\frac{ +1-\sqrt{117} }{2}= \frac{1-10.816653826392}{2} = [tex] \frac{-9.816653826392}{2}= -4.908326913196$

the second number is
$\frac{ -(-1)+\sqrt{-1^2-4(1)(-29)} }{2(1)}=\frac{ +1+\sqrt{1^2+(-116)} }{2(1)}= \frac{1+10.816653826392}{2} = \frac{ +1+\sqrt{117} }{2}= \frac{10.816653826392}{2}=5.908326913196$

the two numbers are
5.908326913196 and
-4.908326913196

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3 years ago

What direction would a sprite go if you constantly decreases its my property?

Elodia [21]

Answer:

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Step-by-step explanation:

Just found this Onlie hope it helps

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