Ask question

Ask question

All categories

3 years ago

8

Pe o piatră stau la soare 3 șopârle. pe o altă piatră stau de două ori mai multe șopârle. Câte șopârle stau la soare pe a doua p

iatră

1 answer:

Elodia [21]3 years ago

7 0

Answer:

hola so the answer is B 1 plus 1 is 2

You might be interested in

A number greater than -5 written as a problem

bazaltina [42]

The answer is x > -5

7 0

2 years ago

Tiles with the letters A,B,C,D,E,F,G and H written on them are placed in a bag. Malik draws out on letter at random. Which state

dusya [7]

Using the probability concept, it is found that the correct statements are given as follows:

The number of possible outcomes is 8.

P(vowel)=1/4

P(vowel) + P(consonant) = 1.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there are eight letters, two of which are vowels and six of which are consonants.

Hence:

P(vowel) = 2/8 = 1/4.

P(consonant) = 6/8 = 3/4.

P(vowel) + P(consonant) = 1/4 + 3/4 = 1.

E is one out eight letters, hence the probability is drawing the tile with E written on it is 1/8.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

4 0

2 years ago

Which of the following could be the lengths of the three sides of a triangle?

OverLord2011 [107]

its b

Step-by-step explanation:

cuz to sides are the exact same then one side is bigger than the others :)

3 0

2 years ago

Read 2 more answers

What is the measure, in degrees, of ∠x in the figure?

gizmo_the_mogwai [7]

Answer:

I believe the answer is 127 degrees.

Step-by-step explanation:

Please give brainliest.

8 0

3 years ago

Read 2 more answers

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

3 years ago