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Olin [163]
2 years ago
6

PLS HELP ME!!!!!! 5w ≥ –6w + 11

Mathematics
1 answer:
vampirchik [111]2 years ago
5 0

Answer:

w ≥ 1

Step-by-step explanation:

Given

5w ≥ - 6w + 11 ( add 6w to both sides )

11w ≥ 11 ( divide both sides by 11 )

w ≥ 1

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Identify whether the series summation of 12 open parentheses 3 over 5 close parentheses to the i minus 1 power from 1 to infinit
Paraphin [41]

Answer:

  This is a convergent geometric series. The sum is 30.

Step-by-step explanation:

In your series, the ratio of terms is 3/5, a value whose magnitude is less than 1. That means the series is convergent. The sum is given by the formula ...

  S = a1/(1 -r)

where a1 is the first term (12) and r is the common ratio (3/5). This gives ...

  S = 12/(1 -3/5) = 12·5/2 = 30

The series is convergent and has a sum of 30.

7 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Sergio039 [100]

Answer:

sqrt41

Step-by-step explanation:

a^2+b^2=c^2

25+16=41

sqrt41

8 0
2 years ago
Read 2 more answers
1.Suppose f(x)=6x^2+2x-7 and g(x)=4x-3.Find the value of f(5)/g(-3)
posledela

Answer:

<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>

Step-by-step explanation:

<u>f</u><u>{</u><u>5</u><u>}</u> = <u>6</u><u>(</u><u>5</u><u>^</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>2</u><u>(</u><u>5</u><u>)</u><u> </u><u>-</u><u> </u><u>7</u>

g{-3}= 4(-3)-3

= <u>6</u><u>(</u><u>2</u><u>5</u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>

-12 - 3

= <u>150</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>

- 15

= <u>1</u><u>5</u><u>3</u>

-15

= <u>-</u><u>5</u><u>1</u>

5

= <em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>

7 0
3 years ago
Please help me <br><br>If 180°&lt;α&lt;270°, cos⁡ α=−8/17, what is sin -α?
rewona [7]

Starting from the fundamental trigonometric equation, we have

\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}

Since 180, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}

Plugging the numbers, we have

\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}

Now, just recall that

\sin(-\alpha)=-\sin(\alpha)

to deduce

\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}

6 0
2 years ago
Read 2 more answers
How much simple interest is earned on an investment of 1,250 if the money is invested for 5 years at an annual interest rate of
Alekssandra [29.7K]
<h3>Answer:  $281.25</h3>

Work Shown:

i = P*r*t

i = 1250*0.045*5

i = 281.25

8 0
2 years ago
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