Answer:
Option B. Amplitude =3 midline is y =2.
Step-by-step explanation:
In the graph attached we have to find the amplitude and midline of the periodic function.
Amplitude of the periodic function = (Distance between two extreme points on y asxis)/2
= (5-(-1))/2 = (5+1)/2 =6/2 =3.
Since amplitude of this function is 3 and by definition amplitude of any periodic function is the distance between the midline and the extreme point of wave on one side.
Therefore midline of the wave function is y=2 from which measurement of the amplitude is 3.
Answer:
the top 3
Step-by-step explanation:
Answer:
the answer should be as follows:
-2(q-3)
the closest answer would be A
Answer:
400
Step-by-step explanation:
│an − L│< ε
│2 + (-1)ⁿ/√n − 2│< 1/20
│(-1)ⁿ/√n│< 1/20
1/√n < 1/20
√n > 20
n > 400
1st term a₁ = - 3.7; common difference d = - 1.3
the nth term a(n) = a₁ +(n-1)d or a(n) = 3.7 + (n-1)(-1.3)
a(n) = - 3.7 - 1.3n + 1.3 ====> -2.4 - 1.3.n Or as per your answer:
a(n) = -1.3.n - 2.4
