Answer:
1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans... Do you satisfied to my given answer
Step-by-step explanation:
Lengths are given to 1dp so the biggest that the lengths could be is 4.65cm and 5.35cm. if you use pythagoras on these to find hypotenuse, this is the upper bound.
Answer:
\mathrm{Domain\:of\:}\:x^3+3x^2-x-3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:<x<\infty \\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:\infty \:\right)\end{bmatrix}
Step-by-step explanation:
If it is the question I just completed it should be A. 76.4
