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Naddika [18.5K]
3 years ago
6

CAN SOMEONE PLEASE HELP ME

Mathematics
1 answer:
k0ka [10]3 years ago
6 0

Answer:

scalene

Step-by-step explanation:

scalene triangle= when triangle leans

right triangle= straight or makes an "L" ( |_ )

equilateral triangle= all sides are equal

isosceles triangle= 2 sides are equal

hope that helps :]

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Please help with this
pentagon [3]

Answer:

B

Step-by-step explanation:

6 0
4 years ago
if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile
Neporo4naja [7]

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

4 0
1 year ago
Two angles are complementary. One angle is ten less than four times the other angle. Find the measure of the larger angle
Nimfa-mama [501]

Answer:

B.70

Step-by-step explanation:

For one or two angles are complementary angle(s), they have to equal 90°.

So, we need to find the larger angle, but what about the other?

Let x be the other angle and y be the angle we are looking for

x + y = 90

Lets look for x first, since one angle is ten less than four times the angle we are looking for or visa versa, we must:

y = 4x - 10

For an exchange, lets take out the y variable for another x variable:

So now we should have x + 4x - 10 = 90

Combine like terms and do cross equation :

x + 4x -10 = 90

5x - 10 = 90

Add 10 to both sides:

5x = 100

100/5 = 20

So <u><em>x=20</em></u>

<u><em></em></u>

Now for y which is what we are looking for,

y = 4x - 10

Since x is 20, plug it in

y = 80 - 10

y=70 is our larger angle

5 0
3 years ago
To find the "break-even point" for solving systems of linear equations, is there an easier way to figure it out instead of makin
Dafna11 [192]
Yes, it is kinda hard to explain so look this up--- linear equation calculator in equation form
8 0
3 years ago
Please help!
DENIUS [597]
A
4x^2/2x is the simplest form

8 0
4 years ago
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