Answer:
The approximate are of the inscribed disk using the regular hexagon is 
Step-by-step explanation:
we know that
we can divide the regular hexagon into 6 identical equilateral triangles
see the attached figure to better understand the problem
The approximate area of the circle is approximately the area of the six equilateral triangles
Remember that
In an equilateral triangle the interior measurement of each angle is 60 degrees
We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon
Let
M ----> the mid-point of AB
OM ----> the perpendicular bisector of AB
x ----> the measure of angle AOM

In the right triangle OAM

so

we have

substitute

Find the area of six equilateral triangles
![A=6[\frac{1}{2}(r)(a)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%28r%29%28a%29%5D)
simplify

we have

substitute

Therefore
The approximate are of the inscribed disk using the regular hexagon is 
To find the slope of g(x), use the slope formula(m):
And plug in two points, I will use:
(0, 2) = (x₁, y₁)
(5, 4) = (x₂, y₂)



You could do the same to find f(x) by finding two points and using the slope formula, or you could use this to tell visibly:

Rise is the number of units you go up(+) or down(-) from each distinguished point
Run is the number of units you go to the right from each distinguished point
If you look at the graph, you can see the points (0, -1) and (3, 1). From each point, you go up 2 units and to the right 3 units (you can make sure by using another point). So the slope of f(x) is 
Whichever line looks more vertical(and is positive) has the greater slope. So the slope of f(x) is greater than the slope of g(x). The answer is option A
Answer:
150(1-x)
Step-by-step explanation:
120 is decreased by d%
Let x = d%
120 - 120*x
120(1-x)
Then it is increased by 25%
(120 (1-x)) +(120 (1-x))*.25
(120 (1-x)) +(30 (1-x))
150(1-x)
Answer:
The answer is m = x + 2kn
Step-by-step explanation:
Rewrite the equation as −
2
k
n + m = x
. Add 2
k
n to both sides of the equation.