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3 years ago

Use this h=graph to graph x > 7

Mathematics

2 answers:

o-na [289]3 years ago

7 0

Hi. This is a random thing because i need things up. Equation for lift is 1/2 times pro times coefficient of lift times area of the wing

HACTEHA [7]3 years ago

5 0

Btw I’m not 100% confident in this answer.

There is a open circle over 7 in the x-axis b cause it is not greater than and less than 7

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Which scenario best matches the linear relationship expressed in the equation y = 13.50x + 300?

Fofino [41]

Answer:

Option C is correct.

Bobby has $300 in the yearbook fund and earns $13.50 for each yearbook sold.

Step-by-step explanation:

Slope intercept form: An equation of line is given by: $y=mx+b$ ......[1] where m is the slope and b is the y-intercept

Given the linear equation: $y = 13.50x+300$

Here, x represents the yearbook sold.

On comparing with the equation [1] we have;

m = $13.50

b =300

therefore, the best scenario best matches the linear relationship is:

Bobby has $300 in the yearbook fund and earns $13.50 for each yearbook sold.

5 0

3 years ago

Read 2 more answers

Use the definition of a Taylor series to find the first four nonzero terms of the series for f(x) centered at the given value of

Black_prince [1.1K]

Answer:

The first four nonzero terms of the Taylor series of $\frac{7}{x + 1}$ around $a=2$ are:

$f\left(x\right)\approx P\left(x\right) = \frac{7}{3}- \frac{7}{9}\left(x-2\right)+\frac{7}{27}\left(x-2\right)^{2}- \frac{7}{81}\left(x-2\right)^{3}+\frac{7}{243}\left(x-2\right)^{4}$

Step-by-step explanation:

The Taylor series of the function f at a (or about a or centered at a) is given by

$f\left(x\right)=\sum\limits_{k=0}^{\infty}\frac{f^{(k)}\left(a\right)}{k!}\left(x-a\right)^k$

To find the first four nonzero terms of the Taylor series of $\frac{7}{x + 1}$ around $a=2$ you must:

In our case,

$f\left(x\right) \approx P\left(x\right) = \sum\limits_{k=0}^{n}\frac{f^{(k)}\left(a\right)}{k!}\left(x-a\right)^k=\sum\limits_{k=0}^{4}\frac{f^{(k)}\left(a\right)}{k!}\left(x-a\right)^k$

So, what we need to do to get the desired polynomial is to calculate the derivatives, evaluate them at the given point, and plug the results into the given formula.

$f^{(0)}\left(x\right)=f\left(x\right)=\frac{7}{x + 1}$

Evaluate the function at the point: $f\left(2\right)=\frac{7}{3}$

$f^{(1)}\left(x\right)=\left(f^{(0)}\left(x\right)\right)^{\prime}=\left(\frac{7}{x + 1}\right)^{\prime}=- \frac{7}{\left(x + 1\right)^{2}}$

Evaluate the function at the point: $\left(f\left(2\right)\right)^{\prime }=- \frac{7}{9}$

$f^{(2)}\left(x\right)=\left(f^{(1)}\left(x\right)\right)^{\prime}=\left(- \frac{7}{\left(x + 1\right)^{2}}\right)^{\prime}=\frac{14}{\left(x + 1\right)^{3}}$

Evaluate the function at the point: $\left(f\left(2\right)\right)^{\prime \prime }=\frac{14}{27}$

$f^{(3)}\left(x\right)=\left(f^{(2)}\left(x\right)\right)^{\prime}=\left(\frac{14}{\left(x + 1\right)^{3}}\right)^{\prime}=- \frac{42}{\left(x + 1\right)^{4}}$

Evaluate the function at the point: $\left(f\left(2\right)\right)^{\prime \prime \prime }=- \frac{14}{27}$

$f^{(4)}\left(x\right)=\left(f^{(3)}\left(x\right)\right)^{\prime}=\left(- \frac{42}{\left(x + 1\right)^{4}}\right)^{\prime}=\frac{168}{\left(x + 1\right)^{5}}$

Evaluate the function at the point: $\left(f\left(2\right)\right)^{\prime \prime \prime \prime }=\frac{56}{81}$

Apply the Taylor series definition:

$f\left(x\right)\approx\frac{\frac{7}{3}}{0!}\left(x-\left(2\right)\right)^{0}+\frac{- \frac{7}{9}}{1!}\left(x-\left(2\right)\right)^{1}+\frac{\frac{14}{27}}{2!}\left(x-\left(2\right)\right)^{2}+\frac{- \frac{14}{27}}{3!}\left(x-\left(2\right)\right)^{3}+\frac{\frac{56}{81}}{4!}\left(x-\left(2\right)\right)^{4}$

The first four nonzero terms of the Taylor series of $\frac{7}{x + 1}$ around $a=2$ are:

$f\left(x\right)\approx P\left(x\right) = \frac{7}{3}- \frac{7}{9}\left(x-2\right)+\frac{7}{27}\left(x-2\right)^{2}- \frac{7}{81}\left(x-2\right)^{3}+\frac{7}{243}\left(x-2\right)^{4}$

8 0

3 years ago

Solve the proportion 2x/5 = 9/15

yuradex [85]

The answer is x=4.5 because 9÷2=4.5 and 4.5×2=9

7 0

3 years ago

Read 2 more answers

Find x when 3^x-1=27

beks73 [17]

Answer:

x=4

Step-by-step explanation:

3^(x-1)=27

=>3^(x-1)=3³

=>(x-1)=3

=>x=4

8 0

3 years ago

Each letter of the word algebra is written on identical slips of paper and placed in a box of a slip of paper selected from the

Aleonysh [2.5K]

Answer:

I have no idea sorry

Step-by-step explanation:

8 0

3 years ago