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horrorfan [7]
3 years ago
10

A, B and C are corners of a parallelogram

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

Step-by-step explanation:

in a parallelogram diagonals bisect each other.

so mid points are same.

Let coordinates of D be (x,y)

mid point of AC=midpoint Of BD

(-2+5)/2=(x+3)/2

x+3=-3

x=-3-3=-6

x=-6

(3-3)/2=(2+y)/2

y+2=0

y=-2

so D is (-6,-2)

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\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}

<h2>33 km</h2>

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So, 0.000033km/yr.

0.000033 × 1,000,000

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An atrium is being designed to house an exhibit of tropical birds. The atrium must enclose 250,000 cubic feet of space, and the
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The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.

<h3>Can this atrium be built in the rectangular plot of land?</h3>

The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.

First, we calculate the volume occupied by the maximum allowable radius:

<em>V' =</em> (8 · π / 3) · (45 ft)³

<em>V' ≈</em> 763407.015 ft³

The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. \blacksquare

To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592

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2 years ago
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Answer: huh ?

Step-by-step explanation:

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3 years ago
Eighty-five more than the square of a number is the same as the square of the quantity that is 17 less than the number. What is
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We can turn this word problem into the following equation:
x^2 + 85 = (x - 17)^2
  x^2 + 85 = x^2 - 34x + 289
           -85                       -85
_______________________
      x^2 = x^2 - 34x + 204                    
     +34x         +34x
_______________________
 x^2 + 34x = x^2 + 204
-x^2             -x^2
____________________
       34x = 204
Divide 34 on both sides
      x = 6.
The number is 6.
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