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3 years ago

A, B and C are corners of a parallelogram

Mathematics

1 answer:

slamgirl [31]3 years ago

5 0

Answer:

Step-by-step explanation:

in a parallelogram diagonals bisect each other.

so mid points are same.

Let coordinates of D be (x,y)

mid point of AC=midpoint Of BD

(-2+5)/2=(x+3)/2

x+3=-3

x=-3-3=-6

x=-6

(3-3)/2=(2+y)/2

y+2=0

y=-2

so D is (-6,-2)

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Find the area .............

Natali5045456 [20]

Answer:

Area of the Trapezoid is= $13.5cm^2$

Step-by-step explanation:

The given figure is in the shape of a trapezoid:

Area of a trapezoid= (1/2)*(Sum of parallel opposite sides)* (Distance between the parallel sides)

The parallel sides are: 6 cm and 3 cm

Distance between parallel sides= 3 cm

Area:

$=\frac{1}{2} *(6+3)*3\\\\=\frac{1}{2}*9*3\\\\=\frac{27}{2} \\\\=13.5 cm^2$

Area of the Trapezoid is= $13.5cm^2$

5 0

3 years ago

A geometric sequence is shown below.

mestny [16]

Answer:

An explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

Step-by-step explanation:

Given the geometric sequence

$-\frac{1}{2},\:-2,\:-8,\:-32,...$

A geometric sequence has a constant ratio, denoted by 'r', and is defined by

$f_n=f_1\cdot r^{n-1}$

Determining the common ratios of all the adjacent terms

$\frac{-2}{-\frac{1}{2}}=4,\:\quad \frac{-8}{-2}=4,\:\quad \frac{-32}{-8}=4$

As the ratio is the same, so

r = 4

Given that f₁ = -1/2

substituting r = 4, and f₁ = -1/2 in the nth term

$f_n=f_1\cdot r^{n-1}$

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

Thus, an explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

8 0

2 years ago

Solve<br> 4(x + 3) = 6<br><br> Make x the subject

Irina-Kira [14]

Answer:

x = -3/2

Step-by-step explanation:

4(x + 3) = 6

4x + 12 = 6

4x = 6 - 12

4x = -6

x = -6/4

x = -3/2

5 0

2 years ago

Read 2 more answers

Please help me with this question I’m so confused

zavuch27 [327]

$s = ut + \frac{1}{2} a {t}^{2} \\ s = 10( \frac{1}{2} ) + \frac{1}{2} ( - 2) {( \frac{1}{2}) }^{2} \\ s = 10( \frac{1}{2} ) + \frac{1}{2} ( - 2)( \frac{1}{4} ) \\ s = 5 + ( - 1)( \frac{1}{4} ) \\ s = 5 + ( - \frac{1}{4} ) \\ s = 5 - \frac{1}{4} \\ s = \frac{20}{4} - \frac{1}{4} \\ s = \frac{19}{4}$