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3 years ago

Determine the amino acid sequence of a polypeptide from the following data:

Chemistry

1 answer:

svlad2 [7]3 years ago

7 0

Solution :

1. It is given that when Edman's reagent is used, it releases PTH-Glycin. The degradation of Edmans is used for the amino acids to sequencing of the peptide/protein and is also removes N terminal amino acid and thus gives us the PTH amino acid product.

Therefore, the first amino acid is Glycine.

2. The Carboxypeptidase A releases the C terminal amino acid, and therefore the last amino acid is Phe.

3. The Cyanogen Bromide helps to chop after the Med residue, therefore the sequence is 1 - 2 - 3 or 2 - 1 - 3.

4. The trysin chops after the basic amino acid - Arg and the Lys unless followed by Proline and so the sequence of the peptide is 1 - 2 - 3 4.

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Select the correct answer. Which equation, when solved, gives 8 for the value of x?

lakkis [162]

Where are the answer choices

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4 years ago

Titanium has five common isotopes: 46Ti (8.0%), 47Ti (7.8%), 48Ti (73.4%), 49Ti (5.5%), 50Ti (5.3%). What is the average atomic

NNADVOKAT [17]

Hey there!:

Isotopes : abundance :

46 Ti 8.0%

47 Ti 7.8 %

48 Ti 73.4 %

49 Ti 5.5 %

50 Ti 5.3 %

Weighted average = ∑ Wa * % / 100

Therefore:

( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =

4792.3 / 100

= 47.923 a.m.u

Hope that helps!

7 0

3 years ago

Humans depend on ecosystems for ecosystem services and

Setler [38]

Explanation:

ok, forest ecosystem always recycle its resources;

dead animals are always returned to the ground, providing fertility of trees & other vegetation for the animals that consume its harvest...this ecosystem provides natural remedies for human ailments, rich soil provides farming, and re using of such, as long as it is not over harvested. The Indians that live there have vast knowledge of their surroundings...

4 0

3 years ago

The molecular weight of a gas that has a density of 5.75 g/l at stp is __________ g/mol.

Ira Lisetskai [31]

Answer : The molecular weight of a gas is, 128.9 g/mole

Explanation : Given,

Density of a gas = 5.75 g/L

First we have to calculate the moles of gas.

At STP,

As, 22.4 liter volume of gas present in 1 mole of gas

So, 1 liter volume of gas present in $\frac{1}{22.4}=0.0446$ mole of gas

Now we have to calculate the molecular weight of a gas.

Formula used :

$\text{Moles of gas}=\frac{\text{Mass of a gas}}{\text{Molecular weight of a gas}}$

Now put all the given values in this formula, we get the molecular weight of a gas.

$0.0446mole=\frac{5.75g}{\text{Molecular weight of a gas}}$

$\text{Molecular weight of a gas}=128.9g/mole$

Therefore, the molecular weight of a gas is, 128.9 g/mole

8 0

3 years ago

Read 2 more answers

Pure ethylene glycol, , is added to 2.00 kg of water in the cooling system of a car. The vapor pressure of the water in the syst

spayn [35]

Answer:

1367.7 g of ethylene glycol was added to the solution

Explanation:

In order to find out the mass of glycol we added, we apply the colligative property of lowering vapor pressure: ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution(P')

525.8 mmHg - 451 mmHg = 451 mmHg . Xm

74.8 mmHg / 451 mmHg = Xm → 0.166 (mole fraction of solute)

Xm = Mole fraction of solute / Moles of solute + Moles of solvent

We can determine the moles of solvent → 2000 g . 1 mol/18 g = 111.1 mol

(Notice we converted the 2kg of water to g)

0.166 = Moles of solute / Moles of solute + 111.1 moles of solvent

0.166 (Moles of solute + 111.1 moles of solvent) = Moles of solute

18.4 moles = Moles of solute - 0.166 moles of solute

18.4 = 0.834 moles of solute → Moles of solute = 18.4/0.834 = 22.06 moles

Let's convert the moles to mass → 62 g/mol . 22.06 mol = 1367.7 g

6 0

3 years ago