The surface area of triangular prism is 117.12 mm²
<u>Explanation:</u>
Base side, a = 9 mm
Base side, b = 6.6 mm
Base side, c = 5.2 mm
Height, h = 4 mm
Total surface area = ?
We know,
Surface area, A = 2 Ab ( a+b+c) h
Ab = √s(s-a) (s-b) (s-c)
s = a+b+c/2
Solving for A
A = ah + b h + ch + 1/2 √ -a⁴ + 2(ab)² + 2(ac)² - b⁴ + 2 (b c)² - c⁴
A = 9.4 + 6.6 X 4 + 5.2 X 4 + 1//2 √ -9⁴ + 2(9 X 6.6)² + 2(9 X 5.2)² - (6.6)⁴ + 2 (6.6 X 5.2)² - (5.2)⁴
A = 117.12 mm²
Therefore, the surface area of triangular prism is 117.12 mm²
Answer:
(2703/64)^3
Step-by-step explanation:
hello :
(5 1/8 x 5 3/8)^3 = (51×53/8×8) ^3 = (2703/64)^3
Answer
0.00145
Step-by-step explanation:
(5 x 10^-4) + (9.5 x 10^-4)
0.0005 + 0.00095
= 0.00145
<h3>Answer: Draw a straight line through (0,-7) and (1,-5)</h3>
Explanation:
You could use any two points you want. For me, the easiest is when x = 0. Plug this into the equation to get
y = 2x-7
y = 2(0)-7
y = -7
So we have x = 0 and y = -7 pair up to get (0,-7) as our first point. This is the y intercept.
Repeat for x = 1
y = 2x-7
y = 2(1)-7
y = -5
So (1,-5) is another point on this line. You only need two points at minimum to graph a straight line.
