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elena-s [515]
3 years ago
5

Please help me find b) and d):

Physics
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

wow it's so hard

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While a car is running, the alternator provides current to the battery and recharges it. which reaction occurs at the anode of a
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While a car is running, the alternator provides current to the battery and recharges it. Reduction  reaction occurs at the anode of a lead-storage battery during this process .

The Lead-acid battery or lead-storage battery is one of the oldest types of rechargeable batteries.

Lead-storage batteries can be classified as secondary batteries. The chemical reactions that occur in secondary cells are reversible. The chemical process of extracting current from a secondary battery (forward reaction) is called discharging. The method of regenerating active material is called charging.

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6 0
2 years ago
Which of the following explains how ions conduct electricity in a solution?
IrinaK [193]

Explanation:

you should give options to find out

5 0
3 years ago
When a force acts on an object from an angle other than either 0° or 180° to the direction of motion:
inn [45]
You must find the component of the force before calculating
4 0
3 years ago
My Notes A container is divided into two equal compartments by a partition. One compartment is initially filled with helium at a
Ostrovityanka [42]

Answer:

final-temperature = T_{f} = 252.51K

Explanation:

we can solve this problem by using the first law of thermodynamics.

    \Delta U= Q-W

Q= heat added

U= internal energy

W= work done by system

                        E_{final}= E_{initial}

<u> C_{v} (N_{2}) C_{v}(He) T_{f} =C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}    (1)</u>

C_{v}(N_{2})=1.04\frac{KJ}{Kg K}

C_{v}(He)=5.193\frac{KJ}{Kg K}

now

From equation 1

T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}

T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}

T_{f} = 252.51K

4 0
4 years ago
A train starts from rest and accelerates uniformly, until it has traveled 3.7 km and acquired a velocity of 26 m/s. What is the
bogdanovich [222]
We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
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676/7400=a
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7 0
3 years ago
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