<span>This is best understood with Newtons Third Law of Motion: for every action there is an equal and opposite reaction. That should allow you to see the answer.</span>
Answer:
that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.
Explanation:
Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.
Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.
In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.
If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.
<span>he theory states that Earth's outermost layer, the lithosphere, is broken into 7 large, rigid pieces called plates: the African, North American, South American, Eurasian, Australian, Antarctic, and Pacific plates. Several minor plates also exist, including the Arabian, Nazca, and Philippines plates. The plates are all moving in different directions and at different speeds</span>
Answer:
Vf = 14 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics, which is independent of the mass of the object.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
x = distance = 10 [m]
Now replacing:
Vf² = 0 + (2*9.81*10)
Vf = 14 [m/s]
