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inysia [295]
3 years ago
12

5 points

Physics
1 answer:
Juli2301 [7.4K]3 years ago
4 0

Answer:

Makes it hard to go to sleep at night

Explanation:

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Hrissie drinks cola every day. She texts the codes printed on the bottle caps to a reward center. For every 40 codes she texts,
andre [41]
<span>Chrissie's behavior is reinforced on a FIXED-RATIO schedule.</span>
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3 years ago
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Electrons are continuously being knocked out of air molecules by cosmic ray particles from space. Once the electrons are free, t
nata0808 [166]

(a) 1.25\cdot 10^{-14} J

The change in potential energy of the electron is given by:

\Delta U=q E d

where

q=1.6\cdot 10^{-19}C is the magnitude of the electron's charge

E=150 N/C is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

\Delta U=(1.6\cdot 10^{-19}C)(150 N/C)(520 m)=1.25\cdot 10^{-14} J

(b) 78 kV

The potential difference the electron has moved through is given by

\Delta V=Ed

where

E=150 N/C is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

\Delta V=Ed=(150 N/C)(520 m)=78,000 V=78 kV

4 0
3 years ago
How to measure the volume of a baseball bat ( need answers ASAP )
vaieri [72.5K]

<em>Measure the amount of water it displaces.</em>

This won't be easy, because the bat floats in water.  But I think you can get around that little problem like this:

-- Get some kind of a tank or tub that's big enough to hold the whole bat under water.

-- Get a heavy weight, like a big wrench or a small rock.  

-- Fill the tub almost to the tippy top with water.

-- Slip the heavy weight into the tub, slowly.  Some water will run over the top and out of the tub.  That's OK ... it's exactly what you want.  If NO water runs over the top, pour some more in, until it runs out and then stops.  You want the tub full to the brimmy rim with the rock at the bottom of it.

-- Take the heavy weight out of the tub.

-- Now set the tub into a bigger tub or a deep pan.  The next time it overflows and some water runs out of it, you'll need to catch that water and measure it.

-- Get a short piece of heavy string.  Tie the heavy weight to somewhere near the middle of the bat.

-- Slowly slide the bat into the water, with the rock tied to it.  The bat needs to go complete underwater.

-- Some more water will run over the top and out of the tub, and INTO the lower tub.  Wait until the overflow stops and everything settles down again.

-- Take the bat (tied to the weight) out of the tub.  Slowly and carefully, so that your hand or your arm doesn't make any MORE water run over and out.

-- Lift the upper tub out of the lower tub.

-- Take the lower tub, with the overflow water in it.  Using a kitchen measuring cup, or a saucepan or a bottle, or anything else with liquid amounts marked on it, measure how much water overflowed into the lower tub.

THAT amount is the volume of the bat.

You may have to do some units conversions.  Like if you need the volume of the bat in cm³ and you used measuring vessels marked in fluid ounces.  But you can find all those conversion factors with a search on Floogle.

8 0
3 years ago
Sail's size and material can make a difference in the effectiveness of how it works because?
Lunna [17]
You need to give more info to your answer so i can help u
7 0
3 years ago
monochromatic light from a distant source is incident on a slit 0.75 mm wide. on screen 2 m away, the distance from the central
hjlf

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

<h3>How to find Wavelength of the light?</h3>

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

To learn more about Wavelength of the light refer to:

brainly.com/question/15413360

#SPJ4

5 0
1 year ago
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