Energy absorbed by the radiologist is 1.775*10^-6J.
To find the answer, we have to know about the radiation.
<h3>How much energy has she absorbed?</h3>
- We have the expression for dose of absorption as,

where; E is the energy absorbed and m is the mass of the body.
- From the above expression, substituting appropriate values given in the question, we get,

Thus, we can conclude that, the Energy absorbed by the radiologist is 1.775*10^-6J.
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Answer:
f = 1 / [ 2*pi*R*C*Sqrt(2*N)
Explanation:
f = 1 / [ 2*pi*R*C*Sqrt(2*N) is the formula. Sorry I answered in English.
M, mass=84 kg
height, h=3.9m
gravity, g= 9.8m/s2
W = F . d
F=force
d=Displacement
W=work done by force
Now by putting the values
F= m g (Acting downward )
d= h (Upward)
W= m g h ( work done against the force)
W= 84•9.8•3.9J
W= 3210.48
Therefore the answer will be 3210.48J.
Max ang. speed(u) = 18 rad/s
final ang. speed(v) = 0
ang. displacement(s) = 220 rad
ang. acceleration = (v^2 - u^2)/2s = -18^2 / 2*220 = -0.7364 rad/s^2
v = u +at
0 = 18 - 0.7364t
t = 18/0.7364
t = 24.44 seconds
Explanation:
The given data is as follows.
C =
R =
ohm
C
Q =
Formula to calculate the time is as follows.
0.135 =
= 7.407
t = 4.00 s
Therefore, we can conclude that time after the resistor is connected will the capacitor is 4.0 sec.