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statuscvo [17]
3 years ago
8

Which products do you think required scientific knowledge to develop? Check all that apply.

Physics
2 answers:
Anvisha [2.4K]3 years ago
7 0

Flash light

Phone

Hair dryer

Glasses

Microwave

gregori [183]3 years ago
6 0
I think all of the above
You might be interested in
The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm (red) and 486 nm (blue). Light f
Georgia [21]

Answer:

Δd = 7.22 10⁻² m

Explanation:

For this exercise we must use the dispersion relationship of a diffraction grating

           d sin θ = m λ

let's use trigonometry

           tan θ = y / L

     

how the angles are small

           tant θ = sinθ  /cos θ = sin θ

we substitute  

           sin θ = y / L

          d y / L = m λ

          y = m λ L / d

let's use direct ruler rule to find the distance between two slits

           

If there are 500 lines in 1 me, what distance is there between two lines

         d = 2/500

        d = 0.004 me = 4 10⁻⁶ m

diffraction gratings are built so that most of the energy is in the first order of diffraction m = 1

let's calculate for each wavelength

λ = 656 nm = 656 10⁻⁹ m

         d₁ = 1 656 10⁻⁹ 1.7 / 4 10⁻⁶

         d₁ = 2.788 10⁻¹ m

λ = 486 nm = 486 10⁻⁹ m

         d₂ = 1 486 10⁻⁹ 1.7 / 4 10⁻⁶

         d₂ = 2.066 10⁻¹ m

the distance between the two lines is

         Δd = d1 -d2

         Δd = (2,788 - 2,066) 10⁻¹

         Δd = 7.22 10⁻² m

6 0
3 years ago
Why don't you hear a sound when you move your hand back and fourth through the air
inessss [21]
Your hand is not capable of moving fast enough for sound to come out of it.
3 0
4 years ago
Read 2 more answers
A net force of 100 n is moving a mass with an acceleration of 5 m/s2. what is the mass of the object? 0.05 kg 20 kg 95 kg 500 kg
dezoksy [38]
F = ma
100n = m(5m/s^2)
100/5 = 20

6 0
4 years ago
Read 2 more answers
A diamond is underwater; A light ray enters one face of the diamond, then travels at an angle of 30 degrees with respect to the
otez555 [7]
According to snells law 

<span>n1 sin theta1 = n2 sin theta2
</span>n1  = 1.333 (water)
<span>n2  = 2.42 (diamond)</span>
 it is given that theta =30 degrees so 
by putting the values we have 

<span>1.333 sin theta = 2.42 sin 30 </span>

<span>sin theta = (2.42/1.333) *0.5 =65.2 degree
</span>so our conclusion is 

<span>the ray's angle of incidence θ1 on the diamond</span> = 65.2 degree.
hope this helps
4 0
4 years ago
Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg
vlabodo [156]

To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

\omega = \frac{v}{R}

Where,

\omega =Angular velocity

v = Lineal Velocity

R = Radius

At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

\alpha = \frac{\omega}{t}

Where

\alpha =Angular acceleration

\omega = Angular velocity

t = Time

Our values are

v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})

v = 16.67m/s

r = 0.25m

t=6s

Replacing at the previous equation we have that the angular velocity is

\omega = \frac{v}{R}

\omega = \frac{ 16.67}{0.25}

\omega = 66.67rad/s

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

\alpha = \frac{\omega}{t}

\alpha = \frac{66.67}{6}

\alpha = 11.11rad/s^2

Therefore the angular acceleration of a point on the outer edge of the tires is 11.11rad/s^2

5 0
3 years ago
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