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Anna007 [38]
3 years ago
6

A cookie contains 150 calories. If you eat no fewer than 2 cookies and no more than 8 cookies, how many calories will you consum

e?
What would the inequality look like
Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer: 300cal ≤ y ≤ 1200 cal

Step-by-step explanation:

Let's define x as the number of cookies that you eat, and y as the number of calories you consume in those cookies.

"if you eat no fewer than 2 cookies..."

This is written as:

2 ≤ x

This means that x can be equal to 2, or larger than 2.

"...and no more than 8 cookies"

This is written as:

x ≤ 8

This means that x can be smaller than 8 or equal to 8.

If we combine those two, we have:

2 ≤ x ≤ 8

And we know that each cookie contains 150 calories, and rememer that these numbers represent number of cookies, then the numbers of calories will be:

2*150 cal  ≤ y ≤ 8*150 cal

300cal ≤ y ≤ 1200 cal.

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I need help with the equation inserted in the picture.
sergij07 [2.7K]

Answer:

x = 4

-4x+21 => 5

Step-by-step explanation:

The given triangle in the picture is isosceles triangle which means that two sides of the triangle are equal.

So,

Side\ 1: -4x+21\\Side\ 2: -4x+21\\Side\ 3: 6\\Perimeter = 16

Now

Putting all the values in equation for perimeter

Side\ 1+Side\ 2+Side\ 3 = 16\\-4x+21 -4x+21 + 6 =16\\-8x +48 = 16\\-8x = 16-48\\-8x = -32\\\frac{-8x}{-8} = \frac{-32}{-8}\\x = 4

Putting x = 4 in side 1

=-4(4)+21\\= -16+21\\=5

Hence,

x = 4

-4x+21 => 5

4 0
3 years ago
Verify the following identity. <br><br> <img src="https://tex.z-dn.net/?f=-%5Cfrac%7Bcos%283x%29%2Bcos%285x%29%7D%7Bsin%283x%29-
kogti [31]

Recall the angle sum identities:

cos(a + b) = cos(a) cos(b) - sin(a) sin(b)

cos(a - b) = cos(a) cos(b) + sin(a) sin(b)

sin(a + b) = sin(a) cos(b) + sin(b) cos(a)

sin(a - b) = sin(a) cos(b) - sin(b) cos(a)

Notice that adding the first two together, and subtract the last from the third, we get two more identities:

cos(a + b) + cos(a - b) = 2 cos(a) cos(b)

sin(a + b) + sin(a - b) = 2 sin(b) cos(a)

Let a = 4x and b = x. Then

cos(5x) + cos(3x) = 2 cos(4x) cos(x)

sin(5x) - sin(3x) = 2 sin(x) cos(4x)

Now,

-\dfrac{\cos(3x)+\cos(5x)}{\sin(3x)-\sin(5x)}=\dfrac{\cos(5x)+\cos(3x)}{\sin(5x)-\sin(3x)}=\dfrac{2\cos(4x)\cos x}{2\sin x\cos(4x)}=\dfrac{\cos x}{\sin x}=\cot x

as required.

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4 years ago
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grin007 [14]

Answer:

i think the given graph is inverse

3 0
2 years ago
Is 0.8009 greater than 0.81?
iVinArrow [24]

Answer:

no

Step-by-step explanation:

because 0<1,

so 0.80...<0.81

8 0
4 years ago
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The answer to your question is (1,3) because I graphed it that is where they intersected at. I hope this helps. 
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3 years ago
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