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Mnenie [13.5K]
3 years ago
5

Zach is building a cage for his gerbil. The area of the cage is 42 square inches.

Mathematics
1 answer:
Airida [17]3 years ago
3 0

Answer:

35

Step-by-step explanation:

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I need help with this ASAP
siniylev [52]

Answer:

Hi there!

The correct answer is 10 units²

Step-by-step explanation:

The area of a triangle is A= 1/2 Base * Height

then you need to replace the values that you given into the formula

A = 1/2 (4)(5)

6 0
3 years ago
Eli is following this recipe to bake bread rolls.
lakkis [162]

Answer:

640g flour

16g salt

12g yeast

60ml oil

Step-by-step explanation:

300 x (4/3) = 400

so multiply all by 4/3

7 0
3 years ago
Find the value of x.
Airida [17]

Answer:

x = 10

Step-by-step explanation:

The 2 chords are equal in length so

7x + 5 = 9x - 15

2x = 20

x = 10

5 0
3 years ago
Answer for 7 and 8 please and explanation if possible
ASHA 777 [7]
7. To find the area of a triangle you use base x height /2.  so the base is 10 and the height is 25 so you do 10 x 25 first which is 250 then divide by 2 which gives you 125 so the area of each pennant is 125 cm^2 ( the ^2 means squared)

8. To find the area of a square you do length x Width. Since for a square all sides are the same the length AND the width are both 450cm. Now you just do 450 x 450 which gives you 202,500 cm^2. BUT it asks for an answer written in SQUARE METRES so you have to change 450cm to metres making it 4.5 metres x 4.5 metres = 20.25  SO THE REAL ANSWER IS 20.25 M^2

Hope this helps you out!


4 0
3 years ago
Read 2 more answers
The horizontal distance between two points.
ankoles [38]

<span>We use the Pythagoras Theorem  to derive a formula for finding the distance between two points in 2- and 3- dimensional space.</span>

Let 

P<span> = (x 1, y 1) </span>

Q<span> = (x 2, y 2) </span>

be two points on the Cartesian plane

<span>Then from the Pythagoras Theorem we find that the distance between P and Q is</span>

        PQ=((x2-x1)^2+(y2-y1)^2)^0.5          

In a similar way

it can be proved that if 

P<span> = (x 1, y 1, z1) and </span>

Q<span> = (x 2, y 2, z2) are two points in the 3-dimensional space, </span>

<span>the distance between P and Q is</span>

 PQ=((x2-x1)^2+(y2-y1)^2+(z2-z1)^2)^0.5   

<span> </span>

 

8 0
4 years ago
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