Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.
This is true. Recording relative positions in most cases will reduce total programming time and make it over all more efficient.
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Answer:
The output of the following code is "The number is SMALL!"
Explanation:
When the following java code is executed. Firstly the program will ask for "Please enter a number" after input the number 15 as per the question, than it check the condition which is "number > 20", if the number is greater than 20 it shows "The number is LARGE!", but the given number is smaller than 20.
