Help please true or false?

May I have help to figure out how to do this? It is confusing! :(

RSB [31]

Answer:

it should be 80%

Step-by-step explanation:

I hope this helps

3 0

2 years ago

Madeline wants to buy a camera for $200 dollars. Her weekly allowance is $15. If she saves $10 each week toward the cost of the

svetlana [45]

Answer:

14 weeks.

Step-by-step explanation:

15x-10=200

add 10 to both sides

15x= 210

divide by 15

x=14 .

5 0

3 years ago

Read 2 more answers

Please help and thank you :)

Lapatulllka [165]

Answer:

500 mL

Step-by-step explanation:

1 L = 1,000 mL

-> We use the formula of L * 1,000 = mL

1,000 mL / 2 = 500 mL

-> We only have half of the L, so we can divide it by 2 to get the correct number of mL

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0

2 years ago

Read 2 more answers

1. a) A car travels at a constant speed. Fill in the table to show how far it travels during different time periods. Time (h) 1

snow_lady [41]

Answer:

I'm not sure what the answer is but I will tell you when I find out

8 0

3 years ago

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Please help ASAP! The terminal side of an angle θ in standard position passes through the point (2,-5). calculate the values of

Troyanec [42]

Answer:

$sin(x)=\frac{opp}{hyp}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21}\\cos(x)=\frac{adj}{hyp}=\frac{2}{\sqrt{21}}=\frac{2\sqrt{21}}{21}\\tan(x)=\frac{opp}{adj}=\frac{5}{2}\\csc(x)=\frac{hyp}{opp}=\frac{\sqrt{21}}{5}\\sec(x)=\frac{hyp}{adj}=\frac{\sqrt{21}}{2}\\cot(x)=\frac{adj}{opp}=\frac{2}{5}$

Step-by-step explanation:

Start by drawing out the triangle on the graph:

(See picture)

(By the drawing you can judge me that I am a really bad artist)

Theta and the side lengths are labeled, the hypotenuse has a length of √21 by Pythagora's theorem. Now, time to put everything to the trigonometric functions:

$sin(x)=\frac{opp}{hyp}=\frac{5}{\sqrt{21}}=\frac{5\sqrt{21}}{21}\\cos(x)=\frac{adj}{hyp}=\frac{2}{\sqrt{21}}=\frac{2\sqrt{21}}{21}\\tan(x)=\frac{opp}{adj}=\frac{5}{2}\\csc(x)=\frac{hyp}{opp}=\frac{\sqrt{21}}{5}\\sec(x)=\frac{hyp}{adj}=\frac{\sqrt{21}}{2}\\cot(x)=\frac{adj}{opp}=\frac{2}{5}$

(Suppose that x is theta as I can't type it)

By some basic understanding that's all that I can do.

3 0

2 years ago