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3 years ago

Pretty please help me!!! i’ll mark brainliest! i tried putting this at 13 points!

Mathematics

2 answers:

tatuchka [14]3 years ago

8 0

Answer:

54°

Step-by-step explanation:

First calculate Angle WMT as: 180° - 117° = 63°

And note that Angle WMT = Angle MWT = 63°

Therefore, Angle T = 180° - 63° - 63°

Angle T = 54°

zloy xaker [14]3 years ago

7 0

Answer:

m∠T = 54°

Step-by-step explanation:

The measure of a straight line is 180°. (Linear angles theorem)

So, m∠WMT + 117° = 180°

m∠WMT = 180 - 117 = 63°

The base angles in an isoceles triangle are equal in measure (base angle theorem)

So,

m∠MWT = m∠WMT

m∠MWT = 63°

The sum of angles in a triangle is 180°. (Sum of angles in a triangle theorem) So,

m∠MWT + m∠WTM + m∠WMT = 180°

Substitute the measures we already found.

63 + m∠WTM + 63 = 180

Simplify.

126 + m∠WTM = 180

m∠WTM = 54°

m∠T = 54°

I hope this helps! Feel free to ask any questions!

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kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

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Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

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$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

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3 years ago

Please help! Limits. Just confirm that an coverages to 2 as n-->infinity

Alexxandr [17]

Answer:

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Step-by-step explanation:

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Advocard [28]

The number of chicken dish is 131 dishes while the number of lobster dishes is 119 dishes

<h3>How to find the number of each type of dish.</h3>

Let

x = number of chicken dish and
y = number of lobster dish

<h3>How to determine the equations for the linear system</h3>

Since it cost $40 per dish for chicken dish, the total cost of chicken dish is 40x.

Also, since it cost $70 per dish for lobster dish, the total cost of lobster dish is 70y

So, the total cost of dish is T = 40x + 70y

Also, we know that the total cost of dish is $13,570.

So, 40x + 70y = 13570 (1)

Also, there are going to be 250 guest at the dinner and thus 250 dishes.

So, the total number of dishes is x + y = 250

So, x + y = 250 (2)

So, the equations of the linear system are

40x + 70y = 13570 (1)

x + y = 250 (2)

<h3>How to determine the solution for the linear system</h3>

Since

40x + 70y = 13570 (1)

x + y = 250 (2)

From (2), x = 250 - y

Substituting x into (1), we have

40x + 70y = 13570 (1)

40(250 - y) + 70y = 13570 (1)

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30y = 13570 - 10000

30y = 3570

y = 3570/30

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Substituting y = 119 into x, we have

x = 250 - y

x = 250 - 119

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