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cricket20 [7]
3 years ago
5

¿ ʇᴉ ǝʌlos noʎ uɐɔ

id="TexFormula1" title=" {12}^{2} + {5}^{2} = x" alt=" {12}^{2} + {5}^{2} = x" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Fed [463]3 years ago
4 0

Answer:

x= 169

Step-by-step explanation:

12*12= 144

5*5= 25

x= 144+25

x= 169

....

Vlad1618 [11]3 years ago
3 0

Answer:

here's the solution :-

=》

x =  {12}^{2}  +  {5}^{2}

=》

x = 144 + 25

=》

x = 169

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Find the measures of the angles in each triangle <br> 2xº<br> 3x°<br> xº
snow_lady [41]

Answer:

x = 30°

The angles:

  • 2x° = 60°
  • 3x° = 90°
  • x° = 30°

Step-by-step explanation:

Hello!

The sum of all the angles in a triangle is 180°. So we can set up an equation for this question.

Solve the equation:

  • 2x° + 3x° + x° = 180°
  • 6x° = 180°
  • x° = 30°

We can replace 30° for all the angles.

The measures are:

  • 2(30°) = 60°
  • 3(30°) = 90°
  • 1(30°) = 30°

4 0
2 years ago
Read 2 more answers
What is the least common multiple of 8 and 12?
MArishka [77]
8:8,16,24,32,40,48,56,64,
12:12,24,36,48
Least common multiple is 24 because it's less then the other common multiples such as 48
4 0
3 years ago
Write 177 as a decimal, rounded to the nearest hundredth.
jek_recluse [69]

Answer:

1.77 is the answer.

hope u got it

3 0
3 years ago
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Find the equation of the line that passes through he points (2,6) and (-2,4)
stepan [7]
First Find slope by using \frac{y2-y1}{x2-x1}

\frac{4-6}{-2-2} = \frac{-2}{-4} =  \frac{1}{2}

Now use point Slope form to find the equation of the line (y-y₁)=m(x-x₁)
(y-6)=\frac{1}{2}(x-2) 
y-6=\frac{1}{2} x-1
y=\frac{1}{2} x+5 is your equation
7 0
3 years ago
Determine whether the equation is exact. If it​ is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e
umka21 [38]

Answer:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

Step-by-step explanation:

You have the following differential equation:

e^t(7y-3t)dt+(2+7e^t)dy=0

This equation can be written as:

Mdt+Ndy=0

where

M=e^t(7y-3t)\\\\N=(2+7e^t)

If the differential equation is exact, it is necessary the following:

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}

Then, you evaluate the partial derivatives:

\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}

The partial derivatives are equal, then, the differential equation is exact.

In order to obtain the solution of the equation you first integrate M or N:

F(t,y)=\int N \partial y = (2 +7e^t)y+g(t)        (1)

Next, you derive the last equation respect to t:

\frac{\partial F(t,y)}{\partial t}=7ye^t+g'(t)

however, the last derivative must be equal to M. From there you can calculate g(t):

\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]

Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:

F(t,y)=(2+7e^t)y+3(1-t)e^t +C

where C is the constant of integration

8 0
4 years ago
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