The correct answer is option A. Three, dumbbell.
The p sublevel has __three_orbitals that are _dunmbbell_-shaped.
The three orbitals of the p sublevel are oriented in three directions along the x, y and Z axis. The orbitals are called px, py and pz. Each p orbital can have a maximum of 2 electrons. Since there are three p orbitals, the p sublevel can have a maximum of 6 electrons.
Answer:
a. 8.37 g,
b. 11.67 g
Explanation:
A) Given:
We need to find the mass of argon.
Firstly, we need to apply the ideal gas law in order to find the total number of moles of gases present in the flask:
From here:
Substituting the variables:
Find the number of moles of hydrogen dividing its mass by the molar mass:
Now find the moles of argon:
Using the molar mass of argon, convert this number into mass:
B) Given:
Firstly, the total pressure is equal to the sum of the vapor pressure of water and the partial pressure of oxygen. Knowing this, solve for the pressure of oxygen:
Use the ideal gas law:
Rearrange the equation, so that we have moles in terms of the mass and the molar mass of oxygen:
Convert the pressure of oxygen into atm knowing that 1 atm = 760 mm Hg. Then:
Now rearrange the ideal gas law equation for mass:
Solve using the variables identified:
Answer:
Acceleration is :
a = 2.89 m/s2
Explanation:
Acceleration : It is the change in the velocity of the object per unit time.
The object starts from the rest , so the initial velocity of the object is zero.
Initial velocity , u = 0
Final velocity = 100 km/h
Change the velocity to m/s because[ time unit is in second(9.60 s)]
1 km = 1000 m
1 hour = 60 x 60 sec = 3600 sec
v = 27.78 m/s
u = 0 m/s
time = 9.60 s
The acceleration"a" is calculated using :
Answer:
87.5 mi/hr
Explanation:
Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.
vf = 60 mi/hr
vi = 0 mi/hr
Δt = 8 secs
a = vf - vi/ Δt
= 60 mi/hr - 0 mi/hr/ 8 secs
= 60 mi/hr / 8 secs
= 7.5 mi/hr^2
Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.
vi = 50 mi/ hr
Δt = 5 secs
a = 7.5 mi/ hr^2
a = vf - vi/ Δt
7.5 = vf - 50 mi/hr / 5 secs
37.5 = vf - 50
87.5 mi/ hr = vf
Yes, they are. They're very significant.