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3 years ago

Select the words that correctly fill in the blanks for this statement:

Chemistry

2 answers:

Lera25 [3.4K]3 years ago

8 0

The correct answer is option A. Three, dumbbell.

The p sublevel has __three_orbitals that are _dunmbbell_-shaped.

The three orbitals of the p sublevel are oriented in three directions along the x, y and Z axis. The orbitals are called px, py and pz. Each p orbital can have a maximum of 2 electrons. Since there are three p orbitals, the p sublevel can have a maximum of 6 electrons.

san4es73 [151]3 years ago

5 0

Answer : The correct option is, three, dumbbell.

Explanation :

As we know that there are many sub-levels which are s, p, d, f, g and so on. The sub-level are oriented in three directions along the x, y and z axis.

The 's' sub-level has one orbital that are spherically shaped.

The 'p' sub-level has three orbitals $(p_x,p_y,p_z)$ that are dumbbell shaped.

The 'd' sub-level has five orbitals $(d_{xy},d_{xz},d_{yz}d_{z^2},d_{x^2-y^2})$ that are double-dumbbell shaped.

The 'f' sub-level has seven orbitals $(f_{x(x^2-3y^2)},f_{y(x^2-3z^2)},f_{y(3x^2-3y^2)},f_{xz^2},f_{z^3},f_{yz^2},f_{xyz})$ that are complex flower shaped.

Hence, the 'p' sub-level has three orbitals that are dumbbell shaped.

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write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithi

diamong [38]

Answer:

First ionization of lithium:

$\text{Li}\;(g)\to \text{Li}^{+} \; (g) + \text{e}^{-}$ .

Second ionization of lithium:

$\text{Li}^{+}\;(g) \to\text{Li}^{2+} \;(g) + \text{e}^{-}$ .

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol $(g)$ next to any atom or ion in the equation.
The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

The products shall contain a gaseous ion with charge +1 $\text{Li}^{+}\;(g)$ as well as an electron $\text{e}^{-}$ .
Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: $\text{Li}\;(g)$ .

Hence the equation: $\text{Li}\;(g) \to \text{Li}^{+}\;(g) + \text{e}^{-}$ .

Second Ionization Energy of Li:

The product shall contain a gaseous ion with charge +2: $\text{Li}^{2+}\;(g)$ as well as an electron $\text{e}^{-}$ .
Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?

The equation for this process is $\text{Li}^{+} \; (g) \to \text{Li}^{2+}\;(g) + \text{e}^{-}$ .

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