All categories

3 years ago

The mass of half mole of electrons is about (mass of electron= 9.1 * 10^-28g)

1 answer:

7 0

One electron has a mass of 9.10938291 x 10^−<span>31 kg. One mole of electrons contains 6.022x10^23 electrons where half of a mole is has 3.011x10^23 electrons. Therefore, the mass of half a mole of electrons would be 2.74x10^-7. Hope this answers the question. Have a nice day.</span>

You might be interested in

What is an example of a neutral mutation? a frog born with white skin a person's inability to break down sugar a red flower with

Naya [18.7K]

Answer:

I think a red flower with one part colored yellow

Explanation:

8 0

2 years ago

One gram of salt in 100 liters of water could be considered a _______________________ solution. A) concentrated B) dilute C) sat

vitfil [10]

Answer:I believe your answer would be option B) dilute. Hope this helps.

Explanation:

3 0

3 years ago

Read 2 more answers

Which of the following is a measure of velocity?

padilas [110]

The correct answer is 30 seconds

6 0

2 years ago

Read 2 more answers

What is the systematic name for TiCl2

Anarel [89]

Answer:

66228

Molecular Formula: TiCl2 or Cl2Ti

Chemical Names: Titanium chloride (TiCl2) 10049-06-6 TiCl2 Titanium(II) chloride dichlorotitanium More...

Molecular Weight: 118.77 g/mol

Dates: Modify: 2019-08-10 Create: 2005-03-26

Explanation:

66228

Molecular Formula: TiCl2 or Cl2Ti

Chemical Names: Titanium chloride (TiCl2) 10049-06-6 TiCl2 Titanium(II) chloride dichlorotitanium More...

Molecular Weight: 118.77 g/mol

Dates: Modify: 2019-08-10 Create: 2005-03-26

8 0

3 years ago

As part of your job you are asked to make 1 liter of a 0.5 molar sucrose solution. how much sucrose (c12h22o11) do you need? use

kakasveta [241]

Answer:- 171 g

Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.

We know that molarity is moles of solute per liter of solution.

If molarity and volume is given then, moles of solute is molarity times volume in liters.

moles of solute = molarity* liters of solution

moles of solute = 0.5*1 = 0.5 moles

To convert the moles to grams we multiply the moles by molar mass.

Molar mass of sucrose = 12(12) + 22(1) + 11(16)

= 144 + 22 + 176

= 342 grams per mol

grams of sucrose required = moles * molar mass

grams of sucrose required = 0.5*342 = 171 g

So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.

6 0

3 years ago