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3 years ago

Give two ways a debit card can be used.

Mathematics

2 answers:

denis23 [38]3 years ago

7 0

Pay for something or receive money from atm

KATRIN_1 [288]3 years ago

5 0

Answer:

pay for something and get money from ATM

Step-by-step explanation:

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Find the focus of the parabola whose equation is y=1/8 x^2

Mama L [17]

Answer:

The focus is: $(0,2)$

Step-by-step explanation:

Given

$y = \frac{1}{8}x^2$

Required

Determine the focus

The focus of a parabola

$(x- h)^2 = 4p(y - k)$

is:

$(h,k+p)$

So, we have:

$y = \frac{1}{8}x^2$

Cross multiply

$8y = x^2$

Rewrite as:

$x^2 = 8y$

Rewrite as:

$(x - 0)^2 = 8(y - 0)$

Express 8 as 4 * 2

$(x - 0)^2 = 4 * 2(y - 0)$

By comparison with: $(x- h)^2 = 4p(y - k)$

$h = 0$ $p =2$ $k = 0$

So, the focus $(h,k+p)$ is:

$(h,k+p) = (0,0+2)$

$(h,k+p) = (0,2)$

7 0

3 years ago

It takes Max three hours to run 30 kilometers. Georges, on the other hand, travels the same distance in 2 hours and 20 minutes.

Mamont248 [21]

George will arrive 20 minutes before Max

It takes Max 3 hours(180 minutes) to run 30 km .

The rate can be calculated as follows:

rate = 30 / 180 = 1/6 km/ min

George uses 2 hours 20 minutes(140 minutes) to run 30 km.

The rate can be calculated as follows:

rate = 30 / 140 = 3/14 km / min

If both are to complete a 15-kilometre race, Therefore,

Max time will be

1 / 6 = 15 / t

t = 15 × 6

t = 90 minutes

George time will be

3/14 = 15 / t

3t = 210

t = 210 / 3

t = 70 minutes

Time difference = 90 - 70 = 20 minutes

Therefore, George will arrive 20 minutes earlier than Max

3 0

3 years ago

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 270 day

dusya [7]

Answer:

a) 281 days.

b) 255 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 270, \sigma = 8$