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Dmitriy789 [7]
3 years ago
5

The vertex of this parabola is at (2, -4). When the y-value is -1, the x-value is 3. What is the coefficient of the squared term

in the parabola's equation?
Mathematics
1 answer:
rjkz [21]3 years ago
5 0

Answer:

3

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

   = 3(x² - 4x + 4) + 4

    = 3x² - 12x + 12 + 4

     = 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

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For a right circular cylinder, if the radius is tripled and the height is shrunk down to half its size, then what is the surface
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Therefore,

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What is the perimeter of the trapezoid if x = 4 and y = -2? Round to the nearest whole number
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For each sequence, find the first 4 terms and the 10th term.<br> a) 3n + 4<br> b) 4n-5
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Answer:

see explanation

Step-by-step explanation:

To find the first 4 terms substitute n = 1, 2, 3, 4 into the formula, that is

(a)

a₁ = 3(1) + 4 = 3 + 4 = 7

a₂ = 3(2) + 4 = 6 + 4 = 10

a₃ = 3(3) + 4 = 9 + 4 = 13

a₄ = 3(4) + 4 = 12 + 4 = 16

Similarly substitute n = 10 for tenth term

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(b)

a₁ = 4(1) - 5 = 4 - 5 = - 1

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a₁₀ = 4(10) - 5 = 40 - 5 = 35

5 0
3 years ago
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