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Ostrovityanka [42]
3 years ago
6

15PTS PLEASE HELP ASAP!

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0

Answer:

Cant see the actual picture.

Step-by-step explanation:

.

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Lewis is 0.9 metres tall.<br>Tim is 0.15 metres taller than Lewis.<br>How tall is Tim?​
Luda [366]

Answer:

D33Z NUTZ

Step-by-step explanation:

BAHHAHAHAHHAH louis is 5'8

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3 years ago
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Suppose that you randomly draw one card from a standard deck of 52 cards. after writing down which card was drawn, you place the
cestrela7 [59]
5:15 because you aren't drawing all of the 52 cards so your proportion would be the probability of drawing at least 5 spade and the 15 cards drawn in all
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3 years ago
At 82°F, a certain insect chirps at a rate of 61 times per minute, and at 91°F, they chirp 124 times per minute. Write an equati
Ganezh [65]

Answer:

y=7x-513

Step-by-step explanation:

Let

x----> the temperature in degrees Fahrenheit

y ---->insect chirping rate in times per minute

we have the ordered pairs

(82,61) and (91,124)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{124-61}{91-82}

m=\frac{63}{9}=7

step 2

Find the equation of the line

we know that

The equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=7  ---> the units are chirps per minute/degree F

take the point (82,61)

substitute and solve for b

61=7(82)+b

61=574+b

b=-513

substitute

y=7x-513

4 0
3 years ago
The circumference of a standard bowling ball is about 27 in. To the nearest unit, how many square inches is the surface area of
Sidana [21]
The surface area of a sphere is S=4 \pi  r^{2} where r is the radius;
The circumference is 2 \pi r=27 in so that r= \frac{27}{2 \pi }=4.5 in using this value we can evaluate the surface area of 1 ball as:
S=4 \pi r^{2} =4 \pi  (4.5)^{2} =254.3  in^{2}
For 100 ball you get: 100*254.3=25430  in^{2}


4 0
2 years ago
Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p
anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

A_{sq}=mp

The area of the triangle is given by the following formula:

A_t=\frac{bh}{2}

Where "b" is the base and "h" is its height. Replacing the values:

A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m

The total area is the sum of both areas:

A=A_{sq}+A_t

replacing the areas:

A=mp+\frac{1}{2}6m

7 0
1 year ago
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