First question seems incomplete :
Answer:
40 ways
Step-by-step explanation:
Question B:
Number of boys = 6
Number of girls = 4
Number of people in committee = 3
Number of ways of selecting committee with atleast 2 girls :
We either have :
(2 girls 1 boy) or (3girls 0 boy)
(4C2 * 6C1) + (4C3 * 6C0)
nCr = n! ÷ (n-r)!r!
4C2 = 4! ÷ 2!2! = 6
6C1 = 6! ÷ 5!1! = 6
4C3 = 4! ÷ 1!3! = 4
6C0 = 6! ÷ 6!0! = 1
(6 * 6) + (4 * 1)
36 + 4
= 40 ways
Answer:
if you have to add it is 17
if you have to divide it is 1.5
if you have to subtract it is 16
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
The given expression is "three less than the quotient of ten and a number, increased by six”
The quotient of ten and a number increased by six is translated into mathematical expression as:
Three less than the quotient of ten and a number, increased by six is
When we substitute n=2, we get:
Divide to get:
Add to get:
Subtract
1234567890233572o7o5y345uo22u.3936584643728284/43794729237932972478864966666666666666666666666666666666663870434573428734907 goood luck!
